Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as
Thus, the starting and finishing time was 2:27 and 7:09 respectively.
I can't see the photo!????????
The answer is 30.
First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.
This may help:
96/3=32
32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93
Answer:
9 mph
Step-by-step explanation:
-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:
#Since t is equal in both, we can do away with t.
#We the divide the downstream equation by the upstream equation as:
Hence, the boat's speed in still water is 9 mph
Answer:
$20.60
Step-by-step explanation:
25.75x20%=5.15
25.75-5.15=20.60
