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3 years ago

Please help, thank you

Mathematics

1 answer:

irina1246 [14]3 years ago

4 0

Answer:

It's kinda hard to see can you type out the question?

Step-by-step explanation:

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AURORKA [14]

X^2+y^2-6x+2y-36=0. Use the equation of the circle (x-h)^2+(y-k)^2=radius^2, center (h,k) is (3,-2)

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4 years ago

How do u do this?! Please show me how <br>Part A and B especially B!

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Check the picture below.

in the picture below, the bottom part

notice, 69° + 21° = 90°, so 21° and 69° are really complementary angles, sharing the same quadrant, meaning for any two sides of lengths say, a,b one angle will have a tangent of say b/a, then the other will have a tangent of a/b.

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3 years ago

What is the product?<br> 6(x2-1) 68x=1<br> HELP ITS FOR EDGE

serious [3.7K]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help!

photoshop1234 [79]

PART A
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5:13
PART B
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15 : 39
Hope this helped! :)

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3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

laiz [17]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

8 0

3 years ago