The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. Suppose
intensity is 8000 units at a distance of 2 miles. What will the intensity be at a distance of 11 miles? Round your answer to the nearest unit
1 answer:
Intensity=k/(distance)² where k is a constant
8000=k/2²
8000=k/4
k=32000
If distance is 11 miles, Intensity=k/11²
=32000/121
=264.46units
≈264units
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36= pi.r^2.h
Volume =pi.r^2.3/4h
Volume =pi.r^2.h.3/4
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5/50=n/110
Do the cross product.
50*n=5(110)
50n=550
n=550/50
n=11
Answer: n=11.