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Nostrana [21]
3 years ago
13

Y=7x+3 7x-6y=-18 substitution

Mathematics
2 answers:
Lynna [10]3 years ago
6 0

Answer:

x=0

y=3

Step-by-step explanation:

y =7x+3       equation 1

7x-6y=-18   equation 2

using equation 1 in equation 2 we have:

7x-6(7x+3)= -18

7x -42x -18 = -18

-35x -18 = -18

-35x = -18 +18

-35x=0

x=0

so we have:

y =7x+3  

y= 7(0) +3

y = 3

Andre45 [30]3 years ago
3 0

Answer:

y=3

x=0

Step-by-step explanation:

we have the following system of equations:

y=7x+3\\7x-6y=-18

the substitution method requires that we take one of the variables of one equation, and substitute that value in the other equation.

in this case taking advantage of the fact that in the first equation the value of y is already cleared, we substitute it in the second equation:

7x-6(7x+3)=-18

and then we solve for x:

7x-42x-18=-18\\-35x-18=-18\\-35x=-18+18\\-35x=0\\x=0

and since x=0 substituting this into the first equation of the system to find the value of y:

y=7(0)+3\\y=3

the answer is y=3 and x=0

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Answer:

The cost of a school banquet is $75+30n, where n is the number of people attending.

If 53 people are attending to visit school banquet, then you have to find the value of given expression at n=53.

At n=53, the value is $(75+30·53)=$1,665.

Step-by-step explanation:

4 0
2 years ago
Again answer as many as you can
Keith_Richards [23]
For #3, it's 5.4 because you divide the total amount of money made by the amount of money earned per hour. 

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3 years ago
Read 2 more answers
What does This equal pls(n+8)+(n-12)
Komok [63]
Combine like terms
2n - 4
7 0
3 years ago
The number of ways 8 cars can be lined up at a toll booth would be computed from
stepladder [879]

Answer: c. 8!

Step-by-step explanation:

We know , that if we line up n things , then the total number of ways to arrange n things in a line is given by :-

n! ( in words :- n factorial)

Therefore , the number of ways 8 cars can be lined up at a toll booth would be 8! .

Hence, the correct answer is c. 8! .

Alternatively , we also use multiplicative principle,

If we line up 8 cars , first we fix one car , then the number of choices for the next place will be 7 , after that we fix second car ,then the number of choices for the next place will be 6 , and so on..

So , the total number of ways to line up 8 cars = 8 x 7 x 6 x 5 x 4 x 3 x 2 x1 = 8!

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5 0
3 years ago
I will mark you as brainlis if you andwer this all.
dimaraw [331]

Answer: See below

Step-by-step explanation:

27.  -(a-3)

28.  (b-1)(b+3)

29.  (c+4)(c+5)

30.  d(d+5)

31.  -(3/4)(2e-5)

Sorry - I don't have time to enter the details.  Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.

For example:  In problem 30:

(5d-20)/(d^2+d-20) * [??]/20d = 1/4

Factor:  

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(d-4)(d+5<u>)</u>       20d

The (d-4), d+5, and d terms cancel, leaving

5/20 = 1/4

7 0
2 years ago
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