Proving that EFGH is a square: points E,F,G,H
separate the sides of the square ABCD into two lines. if AE=BF=CG=DH then
AH=DG=EB=FC and it shows that if we connect the points E,F,G,H to each other with line we will have a square
HAE~EBF~FCG~GDH by rule SAS
Piper rockelle and sawyer reposted us on the devil in squad and part b you guys are you
I think it's A. Sorry if I get it wrong.
Answer:
2 x values
x = 5.85410196
…
x = −
0.85410196
…
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.
Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...
SQ/PQ = TQ/RQ
From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.
(PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem
1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division
-PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)
PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)
