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3 years ago

5

Why does it say join for free if i still have to pay ? like bruh

1 answer:

iragen [17]3 years ago

4 0

Answer:

faxxx

Step-by-step explanation:

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Please help me really quick pleasee<br> answer choices:<br> a)2<br> b)11<br> c)20<br> d)29

mihalych1998 [28]

Answer:

C. $x=20^{\circ}$

Step-by-step explanation:

Angle 6 and angle with measure 45° are vertical angles (opposite angles whan two lines intersect). By Vertical Angles Theorem, vertical angles are congruent, so

$m\angle 6=45^{\circ}$

Angle 6 and angle with measure $5x+35^{\circ}$ are the same side interior angles when two parallel lines are cut by transversal. The same side interior angles add up to 180°, then

$m\angle 6+5x+35^{\circ}=180^{\circ}\\ \\45^{\circ}+5x+35^{\circ}=180^{\circ}\\ \\5x=180^{\circ}-45^{\circ}-35^{\circ}\\ \\5x=100^{\circ}\\ \\x=20^{\circ}$

7 0

3 years ago

Please help me asap!!!

Westkost [7]

Answer: immma guess that its c

super sorry if im wrong

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

2 years ago

Factorise this expression as fully as possible 14t^3 x 6t

kupik [55]

14t^3*6t
= (14*6)*(t^3*t)
= (2*7*2*3)*(t*t*t*t)
= 2*2*3*7*t*t*t*t

6 0

3 years ago

Graph the line with the equation y = 1/6x-5<br><br> PLEASE HELP

quester [9]

Answer:

Step-by-step explanation:

5 0

2 years ago