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Snowcat [4.5K]
4 years ago
12

Let the joint pmf of X and Y be f(x,y)=1/4, (x,y)∈S={(0,0),(1,1),(1,−1),(2,0)}. (a) Are X and Y independent? (b) Calculate Cov(X

,Y) andrho. This exercise also illustrates the fact that dependent random variables can have a correlation coefficient of zero
Mathematics
1 answer:
MrMuchimi4 years ago
8 0

Answer:

rtdjhvjhfdtktcfyukch

Step-by-step explanation:

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Which graph represents an even function?<br>​
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Answer:

Step-by-step explanation:

The first graph (the parabola opening down) represents an even function, since this graph is symmetric with respect to the y-axis.

5 0
3 years ago
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Complete the passage to describe velocity vs time graphs.A velocity vs time graph is a graph that shows the relationship between
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1)Time is plotted on the x-axis in seconds
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4 years ago
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agasfer [191]
The answer will be
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3 years ago
Finish the polynomial by adding one number to make it a perfect square<br><br> x^2+18x+
dsp73

Answer:

81

Step-by-step explanation:

{x}^{2}  + 18x + {(( \frac{1}{2})(18)) }^{2}

{x}^{2}  + 18x +  {9}^{2}

{x}^{2}  + 18x + 81

{(x + 9)}^{2}

6 0
2 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
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