sin(3)+cos(3)sin(3)tan(3)3=0=−cos(3)=−1=−4+,∈ℤ=−12+3
sin(3x)+cos(3x) =0 sin(3x) =−cos(3x) tan(3x) =−1 3x =−
π
4
+kπ,k∈
Z
x =−
π
12
+
k
π
3
Since −<<
−
π
<
x
<
π
, −2≤≤3
−
2
≤
k
≤
3
. Thus, the solution set is
{−34,−512,−12,4,712,1112}
Answer:
√169 OR 13
Step-by-step explanation:
D= √(14-2)^2+(6-1)^2
D= √12^2=5^2
D= √144+25
D= √169 AKA 13
Answer:
bruh
Step-by-step explanation:
b r u h
Answer:
The length of the legs is 8.64cm and 14.64cm respectively
Step-by-step explanation:
I've added an attachment to aid my explanation.
At different intervals, I'll be making reference to it.
Given



From the attachment, we have:

Since, M is the Midpoint

Substitute 17 for AB


Also, from the attachment


Substitute 8.5 for y


--------- (1)
Also, from the attachment

Substitute 8.5 for z


----------- (2)
Subtract (2) from (1)


Make x the subject

Apply Pythagoras Theorem:
We have that:

The above can be replaced with
(see attachment)

Substitute 6 + w for x




Reorder

Solve using quadratic equation:

Where







Split:
or 
or 
or 
But length can't be negative
So:

Recall that: 


<em>Hence, the length of the legs is 8.64cm and 14.64cm respectively</em>
9/10 = z/8
cross multiply
9/10(10)(8) = z/8(8)(10)
9(8) = z(10)
72 = 10z
Isolate the z, divide 10 from both sides
72/10 = 10z/10
z = 72/10
z = 7.2
7.2, or D) is your answer
hope this helps