All categories

3 years ago

Which of the following polynomials has solution that are real numbers ?

1 answer:

7 0

I think that the only polynomial that has a solution that are real numbers is:

B) x² + 4x + 3 = 0
(x + 3) (x + 1) → x² + 1x + 3x + 3 → x² + 4x + 3

(x+3) = 0 → x = -3

(x + 1) = 0 → x = -1

Real numbers are number that are whole numbers, rational and irrational numbers, positive and negative numbers, and even zero.

You might be interested in

Select the statement that describes this expression: 32 ÷ 4 + ( fraction 1 over 2 x 16) − 2

Veronika [31]

Answer:

Step-by-step explanation:

32 ÷ 4 + ( $\frac{1}{2}*16) - 2$ = 8 + (1*8) - 2

= 8 + 8 - 2

= 16 - 2

= 14

6 0

3 years ago

Assume that when adults with smartphones are randomly selected, 51% use them in meetings or classes. If 7 adult smartphone use

Morgarella [4.7K]

Answer:

$P(X \geq 3) = 1-P(X$

If we find the individual probabilities we gotL

$P(X=0)=(7C0)(0.51)^0 (1-0.51)^{7-0}=0.0068$

$P(X=1)=(7C1)(0.51)^1 (1-0.51)^{7-1}=0.0494$

$P(X=2)=(7C2)(0.51)^2 (1-0.51)^{7-2}=0.1543$

And replacing we got:

$P(X \geq 3) = 1- [0.0068 +0.0494 +0.1543]= 0.7895$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=7, p=0.51)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

For this case we want to find this probability:

$P(X \geq 3)$

And we can use the complement rule for this case:

$P(X \geq 3) = 1-P(X$

If we find the individual probabilities we gotL

$P(X=0)=(7C0)(0.51)^0 (1-0.51)^{7-0}=0.0068$

$P(X=1)=(7C1)(0.51)^1 (1-0.51)^{7-1}=0.0494$

$P(X=2)=(7C2)(0.51)^2 (1-0.51)^{7-2}=0.1543$

And replacing we got:

$P(X \geq 3) = 1- [0.0068 +0.0494 +0.1543]= 0.7895$

7 0

3 years ago

The temperature was -13°F and then rose 9°F.<br>what's the temperature?

alexgriva [62]

The temperature rose 22 degrees

3 0

3 years ago

Read 2 more answers

The following two-way table shows the data for the students of two different grades in a school:

Alenkasestr [34]

There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.

There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.

Students in Grade 8 are more likely to be members of the band.

8 0

3 years ago

Read 2 more answers

Let f(x)=x^3+3 and g(x) = 2x^2 + 2x +1. What is g(f(-2))?

emmasim [6.3K]

Answer:

Step-by-step explanation:

This composite function can be easily solved

First solve f(-2)

f(-2)=(-2)³+3

f(-2)=-8+3=-5

Now plug -5 for x in function g(x)

=2(5)²+2(5)+1

=50+10+1

=61

5 0

3 years ago

Read 2 more answers