Which of the following polynomials has solution that are real numbers ?

1 answer:

7 0

I think that the only polynomial that has a solution that are real numbers is:

B) x² + 4x + 3 = 0
(x + 3) (x + 1) → x² + 1x + 3x + 3 → x² + 4x + 3

(x+3) = 0 → x = -3

(x + 1) = 0 → x = -1

Real numbers are number that are whole numbers, rational and irrational numbers, positive and negative numbers, and even zero.

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(2 5/8 + 5/6 + 1 1/8

VLD [36.1K]

<h2> $2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}$ = $3\dfrac{19}{12}$ or, $\dfrac{55}{12}$ </h2>

Step-by-step explanation:

We have,

$2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}$

To find, the value of $2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}$ = ?

∴ $2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}$

= $2+\dfrac{5}{8}+\dfrac{5}{6}+1+\dfrac{1}{8}$

= $(2+1)+(\dfrac{5}{8}+\dfrac{5}{6}+\dfrac{1}{8})$

= 3 + $\dfrac{15+20+3}{24}$

= 3 + $\dfrac{19}{12}$

= $3\dfrac{19}{12}$ or, $\dfrac{55}{12}$

∴ $2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}$ = $3\dfrac{19}{12}$ or, $\dfrac{55}{12}$

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In the figure xy is the bisects wxz. if wxy= (2x+5) and yxz= (3x-25) find wxy

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Answer:

Look down on explanation

Step-by-step explanation:

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Which expression is equivalent to –6x3 • x • y2 • y6?

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<span>–6x^3 • x • y^2 • y^6
= - 6x^4y^8

answer
</span>- 6x^4y^8

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