What is -6x-6+4x=-7x+6

Mathematics

1 answer:

rodikova [14]4 years ago

8 0

Answer:

5x = 12/5

Step-by-step explanation:

Hope I helped! Let me know if I did! ;)

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Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili

pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0

2 years ago

$6.23 + $4.36 + $3.62 + $2.19 + $3.50 + $2.99 + tip: $3.43, + tax: $1.60

Lisa [10]

The answer is $27.92

5 0

3 years ago

9(9h + 4b + 9), for h = 7 and b = 3<br><br> Evaluate

irakobra [83]

So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}

Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)

Now distribute the 9:

567 + 108 + 81

And finally solve as a normal addition problem:

567 + 108 + 81= 756

So, the answer is 756.

I hope this helps:)

6 0

4 years ago

The distribution of the amount of money in savings accounts for University of Alabama students has an average of 950 dollars and

Pavlova-9 [17]

Answer:

Approximately Normal, with a mean of 950 and a standard error of 158.11

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$ .