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pochemuha
4 years ago
14

Consider the total ionic equation below.

Chemistry
2 answers:
Tpy6a [65]4 years ago
4 0

Answer:

The net ionic equation is

Ba²⁺ + CO₃²⁻ → BaCO₃(s)

Explanation:

The chemical reaction described is given as

Ba²⁺ + 2NO₃⁻ + 2Na⁺ + CO₃²⁻ → BaCO₃(s) + 2Na⁺ + 2NO₃⁻

The net ionic equation is obtained by eliminating the ions that appear on both sides of the equation.

And those ions are 2Na⁺ and 2NO₃⁻.

This is a double displacement reaction in which BaNO₃ (aq) reacts with Na₂CO₃ (aq) to form BaCO₃ (s) and NaNO₃ (aq).

The aqueous solutions exist in ionic forms in the reaction and in the net ionic equation, ioms that appear on both sides of the overall equation obviously cancel out.

Hope this Helps!!!

Alexeev081 [22]4 years ago
4 0

Answer:

The correct answer is Ba2+ +2NO-3 =Ba(NO3)2

Explanation:

did it on edu

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Two isotopes of the same element will have the same ATOMIC NUMBER but a different MASS NUMBER.

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Sodium, an alkali metal, and chlorine, a halogen, are both in Period 3 of the periodic table. Which element has
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Answer:

Chlorine has higher ionization energy.

Explanation:

Sodium is present on left side of periodic table in period 3 while chlorine is present on right side of periodic table in period 3.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required. Thus chlorine have higher ionization energy as compared to the sodium.

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The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri
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<u>Answer:</u> The equilibrium concentration of HCl is 2.26\times 10^{-3}M

<u>Explanation:</u>

We are given:

Moles of NH_4Cl(s) = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Molarity of NH_4Cl=\frac{0.564}{1}=0.564M

The given chemical equation follows:

                  NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)

<u>Initial:</u>         0.564

<u>At eqllm:</u>     0.564-x          x              x

The expression of K_c for above equation follows:

K_c=[NH_3][HCl]

The concentration of pure solid and pure liquid is taken as 1.

We are given:

K_c=5.10\times 10^{-6}

Putting values in above equation, we get:

5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M

Negative sign is neglected because concentration cannot be negative.

So, [HCl]=2.26\times 10^{-3}M

Hence, the equilibrium concentration of HCl is 2.26\times 10^{-3}M

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