Answer:
Option A; V = 2.92 L
Explanation:
If we assume a lot of things, like:
The gas is an ideal gas.
The temperature is constant.
The gas does not interchange mass with the environment.
Then we have the relation:
P*V = n*R*T = constant.
Where:
P = pressure
V = volume
n = number of moles
R = constant of the ideal gas
T = temperature.
We know that when P = 0.55 atm, the volume is 5.31 L
Then:
(0.55 atm)*(5.31 L) = constant
Now, when the gas is at standard pressure ( P = 1 atm)
We still have the relation:
P*V = constant = (0.55 atm)*(5.31 L)
(1 atm)*V = (0.55 atm)*(5.31 L)
Now we only need to solve this for V.
V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L
V = 2.92 L
Then the correct option is A.
Answer:
answers are in attachment
Explanation:
1. Synthesis Reaction: In this type of reaction multiple reactant combine to form a single product.
2. Decomposition Reaction: In this type of reaction single compound or reactant break down into new elements or compounds.
3. Replacement Reaction: In this type of reaction an element replace an element in a compound.
4. Even hydrogen is not a metal but it can act as metal in single replacement reaction.
5. In combustion reaction fuel react with oxygen and give heat and light that increase temperature of surrounding.
6. In in-complete combustion reaction fuel react with in-sufficient oxygen and give carbon monoxide and carbon in form of soot.
7. Base is a compound that liberate OH⁻ ion in water.
8. indicators have different color in acid and base depends on pH of the solution
9. Salt and water are the product of neutralization reaction
NaOH + HCl = NaCl + H₂O
10. The pH of neutral solution is 7.
<span>Stoichiometry deals with the quantitative measurement of reactants and products in a chemical reaction. Let suppose you are given with following reaction;
A + 2 B </span>→ 3 C
According to this reaction 1 mole of A reacts with 2 moles of B to produce 3 moles of C. Now using the concept of mole one can easily measure the amount of reactants reacted and the amount of product formed, as...
1 Mole Exactly equals 6.022 × 10²³ particles
1 Mole of Gas (at STP) exactly occupies 22.4 L Volume
1 Mole of any compound exactly equals the molar mass in grams
Therefore, <span>Stoichiometry is very helpful in quantitative analysis.</span>
Could you attach a picture because I can tell you didn't post the entire question.
