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3 years ago

Consider the total ionic equation below.

Chemistry

2 answers:

Tpy6a [65]3 years ago

4 0

Answer:

The net ionic equation is

Ba²⁺ + CO₃²⁻ → BaCO₃(s)

Explanation:

The chemical reaction described is given as

Ba²⁺ + 2NO₃⁻ + 2Na⁺ + CO₃²⁻ → BaCO₃(s) + 2Na⁺ + 2NO₃⁻

The net ionic equation is obtained by eliminating the ions that appear on both sides of the equation.

And those ions are 2Na⁺ and 2NO₃⁻.

This is a double displacement reaction in which BaNO₃ (aq) reacts with Na₂CO₃ (aq) to form BaCO₃ (s) and NaNO₃ (aq).

The aqueous solutions exist in ionic forms in the reaction and in the net ionic equation, ioms that appear on both sides of the overall equation obviously cancel out.

Hope this Helps!!!

Alexeev081 [22]3 years ago

4 0

Answer:

The correct answer is Ba2+ +2NO-3 =Ba(NO3)2

Explanation:

did it on edu

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3 years ago

Simon has collected three samples from the coral reef where he observes marine life. He must determine whether each one is a pur

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2 years ago

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2 years ago

25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?

Mariana [72]

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: $M_{1}$ = 0.0023 M, $V_{1}$ = ?

$V_{2}$ = 15.0 mL, $M_{2}$ = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL$

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

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2 years ago

A sample of C3H8 has 3.28 × 1024 H atoms. How many carbon atoms does the sample contain? What is the total mass of the sample in

sammy [17]

To find the number of carbon atoms, we <span>multiply </span>the 3.28x10^24 by the ratio, 3/8. The total number of carbon atoms is 1.23 x 10^24 atoms. The total mass of the sample is each number of atoms divided by avogadro's number and multiplied by the molar mass of each. The total mass is 29.96 grams.

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3 years ago