Question

A solution of HNO 3 HNO3 is standardized by reaction with pure sodium carbonate. 2 H + + Na 2 CO 3 ⟶ 2 Na + + H 2 O + CO 2 2H++Na2CO3⟶2Na++H2O+CO2 A volume of 25.36 ± 0.05 mL 25.36±0.05 mL of HNO 3 HNO3 solution was required for complete reaction with 0.8311 ± 0.0007 g 0.8311±0.0007 g of Na 2 CO 3 Na2CO3 , (FM 105.988 ± 0.001 g/mol 105.988±0.001 g/mol ). Find the molarity of the HNO 3 HNO3 solution and its absolute uncertainty.

Answer 1

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A solution of HNO3 is standardized by reaction with pure sodium carbonate. 2HNO3 + Na2CO3 ⟶ 2NaNO3 + H2O + CO2. A volume of 25.36 ± 0.05 mL of HNO3 solution was required for complete reaction with 0.8311 ± 0.0007g of Na2CO3, (FM 105.988 ± 0.001 g/mol). Find the molarity of the HNO3 solution and its absolute uncertainty

THE ANSWERS ARE:

MOLARITY= 0.3092mol/l

ABSOLUTE UNCERTAINTY= 0.000873

Explanation:

CALCULATION FOR MOLARITY:

Molarity= gram mole of solute / liters of solution

Where;

Mole= mass/molar mass

mole= 0.8311g/105.988g/mol= 0.0078515mol

MOLARITY= 0.0078415mol/25.36ml = 0.0003092mol/ml = 0.3092mol/l

CALCULATION FOR ABSOLUTE UNCERTAINTY:

Uncertainty (u) =√({0.05/25.36}^2 + {0.001/105.988}^2 + {0.0007/0.8311}^2) × Molarity

Solving brackets gives

(0.00197161+0.00000943503+0.00084226) ×Molarity

Adding up gives

0.002823×Molarity

Therefore;

ABSOLUTE UNCERTAINTY= 0.002823×0.3092= 0.000873