Many elements show very strong similarities to each other.<span>For example, lithium (Li), sodium (Na), and potassium (K) are all soft, very reactive metals.
</span>
Answer:
A combination is certainly possible, but you should not take formal charges so literally
Normally, when a covalent bond is found, the two atoms both bring in one electron. As you identify correctly, in the case of nitric acid that would not be possible completely. If you draw the different possible resonance structures, the most likely structure has a single bond between the nitrogen and an oxygen where the oxygen has 3 lone pairs and both electrons in the bond are donated by the nitrogen. This makes the nitrogen "positive" and that oxygen "negative", but in fact the electrons move more freely in the molecule and charges are more distributed. You will not be able to find "the negatively charged" oxygen atom.
Explanation:
<h2>
<u>PLEASE</u><u> </u><u>MARK</u><u> ME</u><u> BRAINLIEST</u><u> AND</u><u> FOLLOW</u><u> M</u><u> E</u><u> LOTS</u><u> OF</u><u> LOVE</u><u> FROM</u><u> MY</u><u> HEART</u><u> AND</u><u> SOUL</u><u> DARLING</u><u> </u><u>TEJASWI </u><u> HERE</u><u> ❤️</u></h2>
A wave with low energy will also have long wavelengths and low frequencies.
The given in a single photon of a wave is given by Planck's equation:
E = hc/λ
and
E = hf
Where λ is the wavelength and f is the frequency of the photon. This means that energy is directly proportional to the frequency and inversely proportional to the wavelength. Thus, it is visible that photons with a lower frequency and a longer wavelength will have a lower energy.
Answer: 
Explanation:
As we know that,
![-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=-%5Bm_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%5D%3D%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of metal = 100.0 g
= mass of water = 100.0 g
= final temperature = 
= temperature of metal = 
= temperature of water = 
= specific heat of metal = ?
= specific heat of water= 
Now put all the given values in equation (1), we get
![-[100.0\times c_1\times (80-600)]=[100.0\times 4.2\times (80-30)]](https://tex.z-dn.net/?f=-%5B100.0%5Ctimes%20c_1%5Ctimes%20%2880-600%29%5D%3D%5B100.0%5Ctimes%204.2%5Ctimes%20%2880-30%29%5D)
Therefore, the specific heat capacity of metal is 
The answer is 2) 4.7 g/mL because the solid use 17 mL and 80g/17mL is 4,7 g/mL.
