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3 years ago

Joey wants to get a 90 test average in Science. He has already had two tests and he earned

Mathematics

2 answers:

kiruha [24]3 years ago

8 0

I NEED A FREE BRAINLIEST ASAP

Katyanochek1 [597]3 years ago

8 0

Answer:

Joey must get a score of 94 to have a average test score of <em>90</em>.

Step-by-step explanation:

Joey wants a average score of 90.

He already scored 91 and 85 on the previous two tests, and wants to know the score to get a 90 as an average.

Set the equation:

Average = (score of known tests + x)/(amount of tests in all).

Note that: x = score of the next test.

First, Plug in the corresponding numbers to the corresponding terms/variables:

90 = (91 + 85 + x)/(3)

Simplify. Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, multiply 3 to both sides:

90(3) = (91 + 85 + x)/(3) * 3

270 = 91 + 85 + x

Isolate the variable x. Combine like terms:

270 = (91 + 85) + x

270 = 176 + x

Subtract 176 from both sides:

270 (-176) = 176 (-176) + x

x = 270 - 176

x = 94

Joey must get a score of 94 to have a average test score of <em>90</em>.

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$\frac{75}{100} = \frac{90.75}{x} \\ x = \frac{90.75 \times 100}{75} = \frac{9075}{75} = 121$
the answer is 121

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3 years ago

I need an answer asap if you know thanks it is worth a lot of points your welcome

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2 years ago

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A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis

mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

a) A customer is neutral

The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.

The required probability is:

$p=\frac{79}{367}$

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

$p=\frac{106}{367}$

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

$p=\frac{22}{367}$

d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

$p=\frac{33}{111}=\frac{11}{37}$

e) A customer is satisfied or referred.

Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

$p=\frac{227}{367}$

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11 months ago

The price of a swimming pool

Goryan [66]

Answer:

$Sales\:\:Price=List\:\:Price-Discount$
Sales price= $ $1167.25$ List price=L Discount $=19.5\%\:of\:L=0.195L$
$1167.25=L-0.195L$

Step-by-step explanation:

The percentage discount is $19.5\%$

The discount is always given on the list price.

$Sales\:\:Price=List\:\:Price-Discount$

Let the list price be L, then

List price=L

Sales price= $ $1167.25$

Discount $=19.5\%\:of\:L=0.195L$

We substitute into the equation to get:

$1167.25=L-0.195L$

$1167.25=0.805L$

Divide both sides by 0.805

$\frac{1167.25}{0.805}=L$

$1450=L$

The list price of the swimming pool is $1450

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3 years ago

How many whole sandwiches can be made with 2 pounds of cheese if each sandwich has 3 ounces of cheese on it?

pickupchik [31]

10 whole sandwiches can be made with 2 pounds of cheese if each sandwhich has 3 ounces of cheese on it.

2 pounds = 32 ounces

32/3 = 10.67

8 0

2 years ago