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3 years ago

Has endpoints q(4, 10) and s(–2, 3). find the coordinates of the midpoint of . (1, 6.5) (1, 13) (6.5, 3.5) (6.5, 1)

1 answer:

5 0

The midpoint is (1, 6.5)

The best way to find the midpoint of a line is by taking the average of its respective coordinates.

The average of the x coordinates 4 and -2 is 1 because when they are added together and divided by 2 you get 1.

Similarly for the y coordinates, which are 10 and 3. Added together they give an answer of 13 and when that is divided by 2 we get 6.5.

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Is a ratio always a rate?

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No it is not always a rate that was easy

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2 years ago

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What is the solution of this system of linear equations? 3y = x + 6 y – x = 3

Greeley [361]

Hello :
<span>3y = x + 6 ...(1)
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3 years ago

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First to answer correctly gets brainliest

Readme [11.4K]

Answer:

240 $\leq$ 12.5p + 65

14 $\leq\\$ p

Step-by-step explanation:

I'll explain the equation in different parts

12.5p - Since the number of times he visits is unknown, it has to be a variable. With each visit, however, he earns 12.5 points.

65 - This is a set value that remains constant

240 $\leq\\$ - Since he needs AT LEAST 240 points, he needs 240 points or more to get his free ticket

As for solving the equation just use properties of equality

240 $\leq$ 12.5p + 65

175 $\leq$ 12.5p

14 $\leq\\$ p

7 0

3 years ago

Solve for x7(x 2) (x 5)44O -16

babymother [125]

7(x + 2) = 6(x + 5)

7x + 14 = 6x + 30 |subtract 14 from both sides

7x = 6x + 16 |subtract 6x from both sides

x = 16

3 0

3 years ago

Making coconut cookies. The recipe calls for 420 g of coconut and 120 g of sugar. Only has 252 g of coconut. How much sugar must

geniusboy [140]

Answer: 72 grams.

Step-by-step explanation:

Let be "s" the amount of sugar in grams that must be used for 252 grams of coconut to keep the same ratio of coconut to sugar.

Knowing that in the recipe for the coconut cookies, should be 420 grams of coconut and 120 grams of sugar, and you only have 252 grams of coconut, you can set up this proportion to find "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}$

Now, you need to solve for "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}\\\\s(\frac{420grams}{120grams})=252grams\\\\s=(252grams)(\frac{120grams}{420grams})\\\\s=72grams$

4 0

3 years ago