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3 years ago

The polynomial Y=x^2+4x+3 has a repeated factor. True or false

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

<span>x^2+4x+3 = (x + 3)(x +1)....these are factors

answer is FALSE. it does NOT have a repeated factor</span>

natta225 [31]3 years ago

4 0

False
hope this helps

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Step-by-step explanation:

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2 years ago

FIND X AND Y. GIVING BRAINLIEST AND 100 POINTS

aksik [14]

Answer:

here u can look

Mark as brainlist

Step-by-step explanation:

X + y = 120(being alternate angle)

or,X=120-y

then

2x-y=120

or,2(120-y) - y= 120

240-2y-y=120

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2 years ago

Read 2 more answers

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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2 years ago

Please help!!!!! I need to pass this class!!

yulyashka [42]

Angle R is 33 degrees

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3 years ago

The question attached please.

Luda [366]

One adult ticket costs £11 and one child ticket costs £8.5

Step-by-step explanation:

Let,

Adult ticket = a

Child ticket = c

According to given statement;

3a+4c=67 Eqn 1

5a+6c=106 Eqn 2

Multiplying Eqn 1 by 5;

$5(3a+4c=67)\\15a+20c=335\ \ \ Eqn\ 3$

Multiplying Eqn 2 by 3;

$3(5a+6c=106)\\15a+18c=318\ \ \ Eqn\ 4$

Subtracting Eqn 4 from Eqn 3

$(15a+20c)-(15a+18c)=335-318\\15a+20c-15a-18c=17\\2c=17\\$

Dividing both sides by 2

$\frac{2c}{2}=\frac{17}{2}\\c=8.5$

Putting c=8.5 in Eqn 1

$3a+4(8.5)=67\\3a+34=67\\3a=67-34\\3a=33$

Dividing both sides by 3;

$\frac{3a}{3}=\frac{33}{3}\\a=11$

One adult ticket costs £11 and one child ticket costs £8.5

Keywords: Linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

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2 years ago