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Naddik [55]
3 years ago
14

Which figures are polygons? select all that are

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0
Figures A, C and D are all examples of polygons!

I hope this helped! Mark me Brainliest! :) -Raven❤️
You might be interested in
Which of the following statements correctly illustrate the addition property of equality?
liubo4ka [24]

Answer:

x - y + z = 8

2x +3y -z= -2

3x - 2y -9z = 9

Step-by-step explanation:

[1 - 1  1  8]

[2  3  -1 -2]

[3 -2 -9  9]

4 0
2 years ago
Which statement proves that this angle pair is the Corresponding Angles Theorem.<br> Criteria Laval
anzhelika [568]

Answer:

its jess

here is ur ans

first option is your answer

• ANGLE 2 AND ANGLE 6 ARE CONGRUENT BECAUSE THEY ARE CORRESPONDING ANGLES.

5 0
3 years ago
Madison drew some shapes as shown below. which of the following describes madison’s shapes?
taurus [48]

Answer:

what are the following??

Step-by-step explanation:

3 0
2 years ago
The model includes a new park in the center of the city. If the dimensions of the
11111nata11111 [884]

The question is incomplete. Here is the complete question.

As a part of city building refurbishment project,  architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.

The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?

Answer: 81 feet by 153 feet

Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.

In the refurbishment project, the unit scale is given by

1 inch = 9 feet

So, the dimensions of the new park in actual dimensions would be

1 inch = 9 feet

9 inches = x

x = 9.9

x = 81 feet

1 inch = 9 feet

17 inches = y

y = 17.9

y = 153 feet

The actual dimensions of the new park are 81 feet by 153 feet.

6 0
3 years ago
A produce supplier ships boxes of produce to individual customers. The distribution of weights of shipped boxes is approximately
schepotkina [342]

Answer:

0.67(4)+ 36

Option D

Step-by-step explanation:

Given that a producer ships boxes of produce to individual customers.(say x)

X is a normal random variable with mean = 36 and std dev  =4 lbs

By definition of std normal variate we know that

\frac{x-36}{4} is N(0,1)

75th percentile of std normal distribution is

0.675

Hence corresponding x would be

36+0.675(4)

Option D matches with this value

Hence answer is option D

0.67(4)+ 36

5 0
3 years ago
Read 2 more answers
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