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3 years ago

Plz help with this problem

Mathematics

2 answers:

Alinara [238K]3 years ago

6 0

To fond the midpoint add each term to each other and divide by 2.

3+2 = 5

5/2

In 2-i, i can also be written as 1i

So now 8+1 = 9

9/2

The midpoint would be 5/2 + 9/2i

Vlad1618 [11]3 years ago

4 0

To fond the midpoint add each term to each other and divide by 2.

3+2 = 5

5/2

In 2-i, i can also be written as 1i

So now 8+1 = 9

9/2

The midpoint would be 5/2 + 9/2i

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Step-by-step explanation:

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Question 9 of 10

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2 years ago

Find four consecutive even integers such that seven times the first exceeds their sum by 18.

Ganezh [65]

Answer:

10, 12, 14, 16

Step-by-step explanation:

Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.

Lets assume the first number be "x".

As it is even integers

∴ Second consecutive number will be $(x+2)$

Third consecutive number will be $(x+4)$

Fourth consecutive number will be $(x+6)$

Now, as given seven times the first exceeds their sum by 18.

∴ $[x+(x+2)+(x+4)+(x+6)]+18 = 7x$

solving the equation to find the number.

⇒ $[x+(x+2)+(x+4)+(x+6)]+18 = 7x$

Opening parenthesis

$x+x+2+x+4+x+6+18 = 7x$

⇒ $4x+30= 7x$

subtracting both side by 4x

⇒ $30= 3x$

Dividing both side by 3

∴ x= 10.

Hence, subtituting the value x to find four consecutive even integers.

First number is 10

Second consecutive number will be $(10+2)$ = 12

Third consecutive number will be $(10+4)$ = 14

Fourth consecutive number will be $(10+6)$ = 16

∴ Four consecutive even integers are 10,12,14,16.

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