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soldier1979 [14.2K]
3 years ago
8

Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe

r)
A.) the sum of a and b is never rational

B.) The product of a and b is rational

C.) b^2 is sometimes rational

D.) a^2 is always rational

E.) square root of a is never rational

F.) square root of b is never rational
Mathematics
1 answer:
kramer3 years ago
4 0
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
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3 years ago
Mike can complete 217 math problems in 15 minutes.How many problems can he complete in one minute?
Effectus [21]

Find the unit completion rate:

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3 years ago
Tyrell's SAT math score was in the 64th percentile. If all SAT math scores are normally distributed with a mean of 500 and a sta
jarptica [38.1K]

Answer:

P(x < 535.8) = 0.64

P_{64} = 535.8

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.64

P(X<x) = 0.64

P( X < x) = P( z < \displaystyle\frac{x - 500}{10})=0.64  

Calculation the value from standard normal z table, we have,  p(z

\displaystyle\frac{x - 500}{100} = 0.358\\x = 535.8

P(x < 535.8) = 0.64

P_{64} = 535.8

8 0
3 years ago
Each unit in the coordinate plane corresponds to 1 mile. Find the distance from the school to Cherry Street. Round your answer t
GarryVolchara [31]

Answer:

11.2

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points (x_1, y_1) and (x_2,y_2) is equal to \sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is \sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}

3 0
3 years ago
What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)
Ann [662]

Answer:

The midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

Step-by-step explanation:

Given points are (-2,-2)\ and\ (4,6). We need to find the midpoint of the line segment.

The formula of finding midpoints between the point (x_1,y_1)\ and\ (x_2,y_2) is

(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)

W have points (x_1,y_1)=(-2,-2). And (x_2,y_2)=(4,6)

Let us plug the value in Equation (1)

(\frac{-2+4}{2} ),(\frac{-2+6}{2})

(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)

So, the midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

3 0
4 years ago
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