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Zolol [24]
4 years ago
8

How is 1/2+1/4 solved differently than 1/2+1/3?

Mathematics
2 answers:
belka [17]4 years ago
7 0
Well 1/2 plus 1/3 would have more overall rather than 1/2+1/4 simply because 1/3 is bigger than 1/2
disa [49]4 years ago
6 0

Answer:

Refer explanation below.

Step-by-step explanation:

For two integers a and b, denoted LCM(a,b), the LCM is the smallest integer that is divisible by both a and b.

Distributive property: a(b+c)=ab+ac

We are given two expression,

\frac{1}{2}+\frac{1}{4}  and \frac{1}{2}+\frac{1}{3}

We have to show how we solve them differently.

Considering the first expression,

\frac{1}{2}+\frac{1}{4}

Here we can apply the inverse of distributive property,

taking \frac{1}{2} common from the fraction, We get

\Rightarrow \frac{1}{2}(1+\frac{1}{2})

\Rightarrow \frac{1}{2}(\frac{2+1}{2})

\Rightarrow \frac{1}{2}(\frac{3}{2})

\Rightarrow \frac{3}{4}

Now consider the second expression,

\frac{1}{2}+\frac{1}{3}

Take least common factor of denominator that is 2 and 3.

LCM(2,3) = 6 , we get,

\frac{3+2}{6}=\frac{5}{6}

Thus, We can solve the two fraction differently.



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Step-by-step explanation:

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3 years ago
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

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Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

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3 years ago
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Answer: D

Step-by-step explanation:

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B) σ2 =

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=0/10

= 0

σ = √0

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3 years ago
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