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Ulleksa [173]
2 years ago
8

Given a b and m/1 = 42° What is m/6? Enter your answer in the box.

Mathematics
1 answer:
Daniel [21]2 years ago
5 0
Answer:0.166666667 metros

Step-by-step explanation:
espero te ayude
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Which of the following statements best describes an angle that is in standard​ position? A. An angle is in standard position if
lorasvet [3.4K]

Answer: D. an angle is in standard position if the vertex is at the origin of a rectangular coordinate system and the initial side lies along the positive x-axis.




8 0
3 years ago
Need help with all will mark you BRAINLY-EST THNX​
AnnZ [28]

Answer:

1. Rate of change is -5 every step.

2. Rate of change is -5 feet every one hour.

3. Inital water level is 30 ft

Step-by-step explanation:

8 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
2 years ago
Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1) (2.5, 1.5) (3.5, 2.5) (1.5, 2.5) (3.5, 1.5)
Setler79 [48]

Answer:

\boxed {\boxed {\sf (1.5 , 2.5)}}

Step-by-step explanation:

The midpoint is the point that bisects a line segment or divides it into 2 equal halves. The formula is essentially finding the average of the 2 points.

(\frac {x_1+x_2}{2}, \frac {y_1+ y_2}{2})

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 endpoints of the line segment. For this problem, these are (5,4 ) and (-2, 1).

  • x₁= 5
  • y₁= 4
  • x₂= -2
  • y₂= 1

Substitute these values into the formula.

( \frac {5+ -2}{2}, \frac {4+1}{2})

Solve the numerators.

  • 5+ -2 = 5-2 = 3
  • 4+1 = 5

( \frac {3}{2}, \frac{5}{2})

Convert the fractions to decimals.

(1.5, 2.5)

The midpoint of the line segment is (1.5 , 2.5)

3 0
2 years ago
A box is 1 m high, 2.5 m long, and 1.5 m wide, what is its volume?
pochemuha

Answer:

3.75

Step-by-step explanation:

<em>v = lbh  \\ 2.5 \times 1.5 \times 1 \\  = 3.75</em>

6 0
3 years ago
Read 2 more answers
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