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3 years ago

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Mathematics

1 answer:

pav-90 [236]3 years ago

7 0

20-24 ...................

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Have students write an explanation of how to find the slope of a line given the points A(1, 5) and B(−7, 8), also give me the an

Grace [21]

Answer:

3/-8

Step-by-step explanation:

Slope= y2-y2/x2-x1

substitute in: 8-5/-7-1= 3/-8

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3 years ago

A sequence is defined by the recursive formula f(n + 1) = 1.5f(n). Which sequence could be generated using the formula? –12, –18

AlexFokin [52]

It is -16, 17.5, -19, ...

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4 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

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3 years ago

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Question 3 of 10

AlladinOne [14]

Answer:

The answer is 71 degrees

Step-by-step explanation:

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3 years ago

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Which of these statements is true for f(x)=(1/10)^x

White raven [17]

Answer: C. the graph contains (1, 1/10)

Step-by-step explanation:

When x=1, $y=(1/10)^1=1/10$ .

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2 years ago