R2(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0<span><span>r2</span>(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0</span>
<span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=0</span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=<span>0
Now </span></span></span> divide through by <span><span>r≠0</span><span>r≠0</span></span>
and get
<span><span>rcos<span>2ϕ</span>−2cosϕ=0</span><span>rcos<span>2ϕ</span>−2cosϕ=0</span></span>
or
<span><span>r=2<span><span>cosϕ</span><span>cos<span>2ϕ</span></span></span></span><span>r=2<span><span>cosϕ</span><span>cos<span>2<span>ϕ</span></span></span></span></span></span>
Answer:
<h2>-5</h2><h2>-6, -7, -8, -9, etc.</h2>
Step-by-step explanation:
<h2>Hopes this helps. Mark as brainlest plz!</h2>
Answer:
IJ = 12
Step-by-step explanation:
sum the parts of the ratios, 3 + 3 + 4 = 10 parts
Divide HK by 10 to find the value of one part of the ratio.
40 ÷ 10 = 4 ← value of 1 part of ratio , then
IJ = 3 parts = 3 × 4 = 12
To do this, we first want to see how many participants there are in total by adding both males and females.
Now we know that there were 220 total participants, but only 121 were females.
This allows us to set up the fraction 121/220= the percent female.
or 55%
Answer:
38°
Step-by-step explanation:
Delta math
