Answer:
There are 15 numbers of chicken and 25 numbers of bulls.
Step-by-step explanation:
The pen had chickens and bulls. The pen contains 40 animals in total. The number of legs in the pen is 130 .
Let
a = number of chicken
b = number of bull
a + b = 40................(i)
A chicken has 2 legs and a bull has 4 legs.
The total legs can be represented as
2a + 4b = 130...........(ii)
combine the equation
a + b = 40................(i)
2a + 4b = 130...........(ii)
a = 40 - b
insert the value of a in equation(ii)
2(40 - b) + 4b = 130
80 - 2b + 4b = 130
80 + 2b = 130
2b = 130 - 80
2b = 50
divide both sides by 2
b = 50/2
b = 25
Insert the value of b in equation (i)
a + b = 40
a + 25 = 40
a = 40 - 25
a = 15
There are 15 numbers of chicken and 25 numbers of bulls.
(x)+(x+1)+(x+2)=228.
3x+3=228
3x=225
x=75
Integer 1: 75
Integer 2: 76
Integer 3: 77
75+76+77=228
Step-by-step explanation:
y = 8x² + 8x - 96
y = 8(x² + x - 12)
y = 8(x + 4)(x - 3)
When y = 0, 8(x + 4)(x - 3) = 0.
=> x = -4 or x = 3. (B)