Answer: =17⁄50
Step-by Step by step Explanation:
Step 1: 0.34 = 34⁄100
Step 2: Simplify 34⁄100 = 17⁄50
Your answer would be 1,409,240
you would mutpliy 0 and 9 first and keep mutpliying until you get your answer
Answer:
Step-by-step explanation:
Rate of leakage, R(t) = 1400 e^0.06t gallons/h
fraction remains , S(t) = e^(-0.32t)
initial contaminant = 1000 gallon
gallons contaminant present after t hour is S(t) R(t)
G(t) = S(t) R(t)
Put t = 18 hours
Taking log on both the sides
ln G = ln 1400 - 0.26 x 18
ln G = 7.244 - 4.68
ln G = 2.564
G = 13 gallons
Hello,
f(x,y)=2(x²+y²)-25(x²-y²)=0(1)
@f/@x=2*2*(x²+y²)*2x-50x
@f/@y=2*2*(x²+y²)*2y-50y
dy/dx=-(@f/@x)/(@f/@y)=0
==> 2x*(4x²+4y²-25)=0
==>x=0 or x²+y²=25/4 (2)
As (1)==>2*25/4-25(x²-y²)=0
==> x²-y²=1/2 (3)
(2) and (3)=>2x²=27/4 ==>x²=27/8 and y²=23/8
==>x=-√(27/8) and (y=-√(23/8) or y=+√(23/8)
or x=√(27/8) and (y=-√(23/8) or y=+√(23/8)
