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Sladkaya [172]
3 years ago
12

Cci(4) will be soluble in

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0
LIKE DISSOLVES LIKE. Since Ccl4 is non-polar, it'll be soluble in any non-polar solvent. Hope this helps you!
You might be interested in
Help me answer this plz.
boyakko [2]

Answer:

87.58 L of C₂H₂

Explanation:

We'll begin by calculating the number of mole in 250 g of CaC₂.

This can be obtained as follow:

Mass of CaC₂ = 250 g

Molar mass of CaC₂ = 40 + (12×2)

= 40 + 24

= 64 g/mol

Mole of CaC₂ =?

Mole = mass /Molar mass

Mole of CaC₂ = 250 / 64

Mole of CaC₂ = 3.91 moles

Next, the balanced equation for the reaction. This is given below:

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of C₂H₂.

Next, we shall determine the number of mole of C₂H₂ produced by the reaction of 250 g (i.e 3.91 moles) of CaC₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of C₂H₂.

Therefore, 3.91 moles of CaC₂ will also react to produce 3.91 moles of C₂H₂.

Finally, we shall determine the volume of C₂H₂ produced from the reaction. This can be obtained as follow:

Recall:

1 mole of any gas occupy 22.4 L at STP.

1 mole of C₂H₂ occupied 22.4 L at STP.

Therefore, 3.91 moles of C₂H₂ will occupy = 3.91 × 22.4 = 87.58 L

Thus, 87.58 L of C₂H₂ is produced from the reaction.

5 0
3 years ago
If air is a fluid, why do we not include the buoyant force caused by the displacement of air by the objects in this experiment?
uysha [10]

Archimedes' principle allows us to find that the reasons why the thrust is not written when a body is in the air is:

  • The thrust of air is about 800 times less than the thrust of a fluid
  • In general the other forces (weight, tension) are much greater than thrust

Archimedes' principle establishes that the thrust is equal to the weight of the dislodged liquid (fluid)

        B = ρ g V

Where B is the thrust, ρ and V the density and volume of the fluid, respectively, g the acceleration due to gravity.

In the attachment you have a diagram of a system in equilibrium in air and water, we can see that in the two cases for a system in equilibrium

                         B -W = 0

                         B = W

Let's find the value of the thrust in each case and compare

               B_{air} = \rho_{air} g V_{air}

               B_{water} = \rho_{water} \ g V_{water}

Used the density

               \rho_{air} = \  1.26 \  kg/m^3 \\\rho_{water} = 997 kg/m^3

               B_{air} = 1.26 \ g \ V_{air}\\B_{water} = 997 \ g \ V_{water}

Suppose that the volume of the two bodies is the same

               B_{water} = 792 B_{air}r

           

We can see that the thrust in air or other gas is about 800 times less than the thrust in liquids. This is the reason that in many problems the thrust is not written when the body is in the air.

In conclusion, using Archimedes' principle, we find that the reason why the healed thrust is not written for a body is in the air is:

  • The thrust of air is about 800 times less than the thrust of a fluid
  • In general the other forces (weight, tension) are much greater than thrust

Learn more about Archimedes' principle here:

brainly.com/question/787619

5 0
2 years ago
How would you prepared pure water from the mixture of impure water? explain with experiment.<br>​
spayn [35]

Explanation:

Hello, there are alot method to separate the impurities from water. One of those & best method for purification of water is Distillation.

During distillation the given apparatus are set as shown in figure. After arrangement we put the impure water in distillation flask & there are two mouth of flask one is attached to condenser & other is covered. There are two tubes in the middle of the condenser in which water comes in from one and water goes out from the other and this happens continuously. The condenser is used to convert the collected water vapours into liquid water so that it can be collected easily in recieving flask.

\small \sf Thanks  \:  for \:  joining \:  brainly  \: community!

3 0
1 year ago
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
Cloud [144]
<span>it is 3/6 = 0.5 mol/kg of solvent i.e. 0.5 molal <span>solution</span></span>
4 0
3 years ago
Read 2 more answers
Which one is it answer the question
Assoli18 [71]

Answer:

Both are only physical changes.

Explanation:

Nothing about the objects chemically change, and they remain the same.

Their changes arent due to heating/cooling.

5 0
3 years ago
Read 2 more answers
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