2 years ago

4. Shows each line represented as a pair of

Chemistry

1 answer:

tankabanditka [31]2 years ago

8 0

If i’m being honest i’m not exactly sure

You might be interested in

The density of cadmium is 8.65 g/mL, what is the volume of a 33.4 g object made of pure cadmium?

Rzqust [24]

Answer:

Volume = 3.86 ml (Approx)

Explanation:

Given:

Density of cadmium = 8.65 g/ml

Mass of pure object = 33.4 g

Find:

Volume pure cadmium

Computation:

Volume = Mass / Density

Volume = 33.4 / 8.65

Volume = 3.86 ml (Approx)

6 0

3 years ago

I exercise

KatRina [158]

Explanation:

sorry po king Hindi kopo ma sagot

7 0

2 years ago

The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P

expeople1 [14]

Answer : The ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

Solution : Given,

$K_p=1.5\times 10^6$

$p_{O_2}$ = 0.21 atm

The given equilibrium reaction is,

$NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}$

Now put all the given values in this expression, we get:

$1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}$

$\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}$

$\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5$

Therefore, the ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

5 0

3 years ago

When a liquid is heated the average what? Of energy of its particles will increase

weeeeeb [17]

When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises.

8 0

3 years ago

When NH NO3(aq) reacts to form N2O(g) and H2O(1), 150 kJ of energy are evolved for each mole of NH NO3(aq) that reacts.

amid [387]

Billy bobbbbbbbbbbbbbbbbbbbbbbb

4 0

2 years ago