During nuclear fusion on a protostar, _hydrogen__ fuse to form helium atoms
There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.
Answer:
Joule-Thomson coefficient for an ideal gas:

Explanation:
Joule-Thomson coefficient can be defined as change of temperature with respect to pressure at constant enthalpy.
Thus,
![\mu_{J.T} = \left [\frac{\partial T}{\partial P} \right ]_H](https://tex.z-dn.net/?f=%5Cmu_%7BJ.T%7D%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%20%5Cright%20%5D_H)
Also,


![dH= \left [\frac{\partial H}{\partial T}\right ]_P dT + \left [\frac{\partial H}{\partial P}\right ]_T dT](https://tex.z-dn.net/?f=dH%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20T%7D%5Cright%20%5D_P%20dT%20%2B%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20dT)
Also,
is defined as:
![C_p = \left [\frac{\partial H}{\partial T}\right ]_P](https://tex.z-dn.net/?f=C_p%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20T%7D%5Cright%20%5D_P)

![dH= C_p dT + \left [\frac{\partial H}{\partial P}\right ]_T dT](https://tex.z-dn.net/?f=dH%3D%20C_p%20dT%20%2B%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20dT)
Acoording to defination, the ethalpy is constant which means 

![\left [\frac{\partial H}{\partial P}\right ]_T = -C_p\times \left [\frac{\partial T}{\partial P}\right ]_H](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D%20-C_p%5Ctimes%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_H)

![\mu_{J.T} = \left [\frac{\partial T}{\partial P}\right ]_H](https://tex.z-dn.net/?f=%5Cmu_%7BJ.T%7D%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_H)

![\left [\frac{\partial H}{\partial P}\right ]_T =-\mu_{J.T}\times C_p](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D-%5Cmu_%7BJ.T%7D%5Ctimes%20C_p)
For an ideal gas,
![\left [\frac{\partial H}{\partial P}\right ]_T = 0](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D%200)
So,

Thus,
≠0. So,

Answer:
The carbons of the acetyl group oxidize which generate CO2, and in turn H2O.
Explanation:
The pyruvic acid that is generated during glycolysis enters the mitochondria. Inside this organelle, the acid molecules undergo a process called oxidative decaborxylation in which an enzyme of several cofactors is involved, one of which is coenzyme A. Pyruvic acid is transformed into an acetyl molecule and these are been introduced to the begining of the Krebs Cycle where the acetyl-group (2C) from acetyl-CoA is transferred to oxaloacetate (4C) to produce citrate (6C). As the molecule cycles the two carbons of the acetyl oxidize and are released in the form of CO2. Then the energy of the Krebs cycle becomes sufficient to reduce three NAD +, which means that three NADH molecules are formed. Although a small portion of energy is used to generate ATP, most of it is used to reduce not only the NAD + but also the FAD which, if oxidized, passes to its reduced state, FADH2
Answer:For atoms and molecules, the width of spectral lines is governed mainly by the broadening of the energy levels of the atoms or molecules during interactions with surrounding particles and by the broadening of the spectral lines as a result of the Doppler effect.
Explanation: