Answer:
Energy emitted by photon = 45.06 × 10−32 J
Explanation:
Energy of photon is given by E = hf
where
h is the Planck's constant whose value is 6.626×10−34J⋅s
f is the frequency of photon
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given that
f = 6.8 x 104 Hz
1 HZ = 1 s^-1
E = 6.626×10−34J⋅s * 6.8 x 10^4 Hz
E = 45.06 × 10−32 J
Thus,
Energy emitted by photon is 45.06 × 10−32 J
Answer:
C. He takes a rough sketch and uses his own artistic skill to draw it more clearly
There is no hydrogen in ammonium sulfide it is just 1 ammonium and 1 sulfer
B. oxidizing
In the reaction the oxidizing agent is reduced.
Fale, they alwayd cotain carbon.
Hope this helps