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2 years ago

13

Please I need some help

1 answer:

laiz [17]2 years ago

7 0

For the first question, all you need to know is that the (amount you want) divided by (the amount of cards total) is the probability of getting the amount you want at random. for example, if there are 3 red marbles in a bag of ten marbles, you divide 3 by 10 (0.30) the probability of picking up a red marble is 30%. try adding up how many cards you want to pick up by the number of cards total.

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John can write 35 words per minute write an expression for the number of minutes it takes John to type x words

lukranit [14]

It is y(1/x) minutes

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2 years ago

An airplane's change in altitude before landing in shown in the table. What equation represents this change in altitude

Ray Of Light [21]

Answer

-4,000

Step-by-step explanation:

Just subtract 35,000 and 31,000 or 27,000 and 21,000 and get 4,000. Since the altitude is going down, it'll be negative.

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3 years ago

Find the volume of the prism, using a calculator if necessary.

Minchanka [31]

Answer:

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2 years ago

What is the midpoint

antoniya [11.8K]

<u>Answer:</u>

(0.5, -0.5)

<u>Step-by-step explanation:</u>

We are given a line segment on the graph with two known points (ending points) and we are to find its mid point.

We know the formula for the mid point:

$Midpoint = ( \frac {x_1 + x_2} {2} ,\frac {y_1 + y_2} {2} )$

Substituting the coordinates of the given points in the above formula:

Mid point = $(\frac {5 + (-4) } {2} , \frac { 6 + (-7)} {2} )$ = (0.5, -0.5)

8 0

3 years ago

Read 2 more answers

a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

M= (c^2)/8 which is intern equal to 2 $\sqrt{2}$

Step-by-step explanation:

Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}4d\theta$

$=8\pi$

Therefore;

Mxy= $\int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta$

z-bar = 8/3

M= 8 $\pi$ dividing it into two volume gives us = 4 $\pi$

means $4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta$

$4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)$

c=2 $\sqrt{2}$

5 0

3 years ago