There will be five rows of 8 bean plants per row, four rows of 8 tomato plants per row, and four rows of 4 tomato plants per row. I hope this helps!
Step-by-step explanation:
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Answer:
The problem:
Find 
if 
,
![h(x)=\sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B3%7D)
, and
![f(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
.
Step-by-step explanation:
Replace 
in with since we are asked to find 
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:
![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
![\sqrt[3]{x+3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D)
which is the required result for 
.
Rearrange equation to get
6x>12 so
x>2
X=16log i’m guessing not sure:)
