Answer:
Greatest Common Factor is 
Step-by-step explanation:
Greatest Common Factor is the highest factor that will divide all the numbers. To find the Greatest common factor, first we need to find out the numbers that all the values have in common.
Factors of 4k=1, 2, 4 and k
Factors of 18k=1, 2 , 3, 6, 9, 18 and k
Factors of 12=1, 2, 3, 4, 6 and 12
Common factors are = 1 and 2.
Therefore,
Greatest Common Factor = 
=
Answer:
Step-by-step explanation:
line graph- the decrease of attendance
bar graph-the number of students who participate in different sports
line plot-the list of heights of a group of 80 adults
steam and leaf plot- the number of dogs for students
This response is based upon your having had some background in calculus. "dx" is not introduced before that.
Take a look at the sample function y = f(x) = x^2 + 9. Here x is the independent variable; the dependent variable y changes with x.
Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is
b-a
dx = ---------- , and that dx becomes smaller and smaller as the number of
n subintervals increases.
Once again, this all makes sense only if you've begun calculus (particularly integral calculus). Do not try to relate it to earlier math courses.
1. AD/DB=CE/EB
given
2. AD/DB+1=CE/EB+1
Addition Property of Equality
3. AD+DB/DB=CE+EB/EB
using common denominators
4. AB = AD + DB
CB = CE + EB
segment addition
5. AB/DB=CB/EB
Substitution Property of Equality
6.ABC DBE
Reflexive Property of Congruence
7. ABC ~ DBE
SAS similarity criterion
<span>8. </span>
Corresponding angles of similar triangles are congruent.
9. DE|| AC
<span>If the corresponding angles formed by </span>