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Rufina [12.5K]
3 years ago
13

Given that the the graph represents a system of equations on a coordinate plane, how many solutions does the system have?

Mathematics
1 answer:
nalin [4]3 years ago
8 0
Wheres the graph? i cant help if theres no graph, sorry

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Convert 3510 to number in base 2​
FrozenT [24]

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I think its 56.1248608016

Step-by-step explanation:

Use desmos.com

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Alma bought 6 gallons of gasoline for $19.14. What was the unit price of this gasoline?
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If 3x+2=11<br> then x= ?
leonid [27]

Answer:

X=3

Step-by-step explanation:

What you have to do is minus 2 from 11 and you get 9

Now divide 3 into 9 and you get 3

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8 0
3 years ago
Read 2 more answers
Complete the rational operation <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7Bx%20-%205%7D%20%20-%20%20%5Cfrac%7Bx%7
prisoha [69]
We have
                             3 / (x-5) - x/5
We make the GCF and we have
                                    15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
                                  = [ 15 - x(x-5) ]  [5(x-5)]
                                  = [ 15 - x^2 + 5x] / [ 5 (x-5) ]
                                  = [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
6 0
3 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
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