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2 years ago

LOTS OF POINTS!!!!!!!!Please help asap!!!!! I need to solve for x

Mathematics

1 answer:

lozanna [386]2 years ago

4 0

Answer:

x = 1 11/15

Step-by-step explanation:

Using ratios of similar triangles

3 5.2

-------- = ----------

4 (5.2 + x)

Using cross products

3 * (5.2 + x) = 5.2 * 4

Distribute

15.6 + 3x = 20.8

Subtract 15.6 from each side

15.6-15.6 + 3x = 20.8 -15.6

3x =5.2

Divide each side by 3

3x/3 = 5.2/3

x = 5.2/3

x=52/30

x = 26/15

x = 1 11/15

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Which of the following represents the diagram below? HELP ASAP!!

anastassius [24]

Answer: A

Step-by-step explanation:

The shape in the diagram is a square, a square is a shape with all sides being equal. To find out the length of all the sides, just count how many units make up one side since they're the same.

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3 years ago

F(x) = x2 − 8x + 15 g(x) = x − 3 h(x) = f(x) ÷g(x)

olasank [31]

Hello :
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2 years ago

Read 2 more answers

I just want the final answer

Marianna [84]

I'm just eyeballing the chart but imma guess .9

7 0

3 years ago

Simplify the expression. Quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity se

Art [367]

Answer:

D. 1

Step-by-step explanation:

We have the expression, $\frac{\csc^{2}x\sec^{2}x}{\sec^{2}x+\csc^{2}x}$

We get, eliminating the cosecant function,

$\frac{\sec^{2}x}{\frac{\sec^{2}x}{\csc^{2}x}+1}$

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,

i.e. $\frac{\sec^{2}x}{\frac{\sin^{2}x}{\cos^{2}x}+1}$

i.e. $\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}$

Since, we know that, $\sin^{2}x+\cos^{2}x=1$

Thus,

$\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}=1$

So, after simplifying, we get that the result is 1.

Hence, option D is correct.

3 0

2 years ago

A 99% confidence interval for the sugar content (per 5 oz. serving) of a shipment of strawberries is 5.9 to 8.3 grams.

gavmur [86]

Answer:

Sample mean = 7.1

Margin of error = 0.465

Step-by-step explanation:

Formula for confidence interval is;

CI = x¯ ± zE

Where;

x¯ is sample mean

z is critical value at confidence level

E is margin of error.

z for 99% Cl is 2.58

We are told the CI is 5.9 to 8.3.

Thus;

5.9 = x¯ - 2.58E - - - - (1)

8.3 = x¯ + 2.58E - - - - (2)

Add both equations together to get;

14.2 = 2x¯

x¯ = 14.2/2

x¯ = 7.1

Put 7.1 for x¯ in eq 1 to get;

5.9 = 7.1 - 2.58E

7.1 - 5.9 = 2.58E

E = 1.2/2.58

E = 0.465

5 0

2 years ago