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Please help me find the perimeter!! :)

Mathematics

1 answer:

Sholpan [36]2 years ago

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Try to count your square and use the formula lxwxh

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2 years ago

What is the 4th term in the sequence? <br><br> C(1)=56<br> C(n)= c(n-1)•1/2

Anton [14]

Answer:

The 4th term is 7

Step-by-step explanation:

we have

$C(n)=C(n-1)\frac{1}{2}$

$C(1)=56$

step 1

Find C(2)

For n=2

$C(2)=C(1)\frac{1}{2}$

$C(2)=(56)\frac{1}{2}=28$

step 2

Find C(3)

For n=3

$C(3)=C(2)\frac{1}{2}$

$C(3)=(28)\frac{1}{2}=14$

step 3

Find C(4)

For n=4

$C(4)=C(3)\frac{1}{2}$

$C(4)=(14)\frac{1}{2}=7$

therefore

The 4th term is 7

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2 years ago

Solve for the variable x F=kx-kx0

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Answer: x = f/k + 1

Step-by-step explanation:

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2 years ago

The area of a rectangle is 14 m2 , and the length of the rectangle is 3 m less than double the width. find the dimensions of the

muminat

Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

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2 years ago