Question

Which equation describes a line that passes through (-6, 8) and is parallel to the line described by y = 2x − 4?

Answer 1

Answer:

hey, there!

Step-by-step explanation:

The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4

The equation for point (-6,8) is,

(y-8)= m1(x+6)...........(i)

and given equation is y = 2x-4............(ii)

Now, from equation (ii).

slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.

Now, For perpendicular,

m1×m2= -1

m1×2= -1

Therefore, m1 = -1/2.

Putting, the value of m1 in equation (i).

(y-8) = -1/2×(x+6)

2(y-8)= -1(x+6)

2y - 16 = -x -6

x+2y-10 = 0......... is the required equation.

Hope it helps...