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monitta
3 years ago
10

Angela left for work at 8:30 a.m. She returned to school at 11:30 a.m. How long was Angela at work?

Mathematics
2 answers:
Dimas [21]3 years ago
8 0

Answer:

Angela was at work for 15 hrs.

nata0808 [166]3 years ago
7 0

Step-by-step explanation:

Since she was at work at 8:30 a.m and then she returned to school at 11:30 a.m she took 3 hours at work

11:30 a.m - 8: 30 a.m. = 3 hours of difference

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Solve for the product of 1,325 x 10₁ = ________. Then, explain how you moved the decimal to get the product.
professor190 [17]

Answer:

13,250.0

When we multiply a number with 10, the decimal place of the original number will move to the right by one step.

Step-by-step explanation:

We can write the number 1,325 as 1325.00

Now, we have to solve the product of 1,325 \times 10^{1}

So, 1,325 \times 10^{1}

= 1,325.00 \times 10^{1}

= 13,250.0 (Answer)

Therefore, when we multiply a number with 10, the decimal place of the original number will move to the right by one step and when we divide a number with 10, then the decimal place of the original number will move by one step to the left. (Answer)

3 0
3 years ago
2x - 18x + 14y - 19<br> Is it equivalent
jek_recluse [69]

Answer:

Step-by-step explanation:

You can simplify this by collecting the like terms. The only like terms are the pair 2x and 18 x

2x-18x = -16x

Now, put them back together,

-16x + 14y-19

4 0
3 years ago
Read 2 more answers
Find M of angle ABC
pochemuha

Answer:

25

Step-by-step explanation:

\sf Answer \begin{cases}\sf \rightarrowtail \:( 3x - 6) + (2x + 25) + (x + 11) = 180 \\  \sf \rightarrowtail \: 3x - 6 + 2x + 25 + x + 11 = 180 \\  \sf \rightarrowtail \: 3x + 2x + x - 6 + 25 + 11 = 180 \\  \sf \rightarrowtail \: 6x + 30 = 180 \\  \sf \rightarrowtail \: 6x = 180 - 30 \\  \sf \rightarrowtail \: 6x = 150 \\  \sf \rightarrowtail \: x =  \frac{150}{6}  \\  \sf \rightarrowtail \: x = 25\end{cases}

5 0
3 years ago
Solve the following application problem. Be sure to show your system of equations and the steps to solve the problem.
ololo11 [35]

Answer:

  • boat: 6 mph
  • current: 2 mph

Step-by-step explanation:

The relationship between time, speed, and distance is ...

  speed = distance/time

For boat speed b and current speed c, the speed downstream is ...

  b +c = (16 mi)/(2 h) = 8 mi/h

The speed upstream is ...

  b -c = (16 mi)/(4 h) = 4 mi/h

Adding the two equations eliminates the c term:

  2b = 12 mi/h

  b = 6 mi/h . . . . . divide by 2

Solving the second equation for c, we get ...

  c = b -4 mi/h = 6 mi/h -4 mi/h = 2 mi/h

The speed of the boat in still water is 6 mi/h; the current is 2 mi/h.

6 0
3 years ago
There is a quadrilateral MNPQ in which side MN is congruent to side PQ and side NP is parallel to side MQ. The diagonal MP and t
8_murik_8 [283]

Answer: QN = 12

Step-by-step explanation: This quadrilateral is a paralelogram because its 2 opposite sides (NP and MQ) are parallel and the other 2 (MN and PQ) are congruent.

In paralelogram, diagonals bisect each other, which means QR = RN.

If QR = RN:

QR = 6

Then,

QN = QR + RN

QN = 6 + 6

QN = 12

<u>The diagonal QN of quadrilateral MNPQ is </u><u>QN = 12</u><u>.</u>

5 0
3 years ago
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