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monitta
3 years ago
10

Angela left for work at 8:30 a.m. She returned to school at 11:30 a.m. How long was Angela at work?

Mathematics
2 answers:
Dimas [21]3 years ago
8 0

Answer:

Angela was at work for 15 hrs.

nata0808 [166]3 years ago
7 0

Step-by-step explanation:

Since she was at work at 8:30 a.m and then she returned to school at 11:30 a.m she took 3 hours at work

11:30 a.m - 8: 30 a.m. = 3 hours of difference

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write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)
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The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is y - 3 = \frac{-7x}{2}+ \frac{21}{4}

<h3><u>Solution:</u></h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

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So let us find the midpoint of A(-2,2) and B(5,4)

<em><u>The midpoint formula for given two points is given as:</u></em>

\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Substituting the given points A(-2,2) and B(5,4)

m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x - x_1)

\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)

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