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Mariana [72]
3 years ago
10

Please Help, Im having trouble with this

Mathematics
2 answers:
Sauron [17]3 years ago
6 0
Troubles with what tho?
Sedaia [141]3 years ago
3 0

Answer:

1 7/8 can be written as 8*1+7/8=15/8=1.875

Step-by-step explanation:

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kifflom [539]
1 6 dis 9/3 please please come out with the best way
8 0
3 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
A company orders 25 boxed lunches from a deli for $185. If each boxed lunch costs the same amount, what is the unit cost of each
guapka [62]

Answer:

7.40

Step-by-step explanation:

Divide 185 by 25 to get unit rate

7 0
3 years ago
Simplify the following: (-83)2​
Anika [276]
The answer is -166, your welcome
8 0
3 years ago
Due to nght please help part 2 !
mash [69]

Answer:

t≤ 9

Step-by-step explanation:

3.5+4t≤ 39.5

subtract 3.5 from each side

4t≤ 36

divide each side by 4

t≤ 9

5 0
3 years ago
Read 2 more answers
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