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3 years ago

15

A string of length 2.00 m is stretched between two fixed points with enough tension to make the transverse wave speed 40.0 m/s o

n the string. What are the wavelength and frequency of:
a. the fundamental mode of the standing wave.
b. 1st overtone
c. The 3rd harmonic

1 answer:

Solnce55 [7]3 years ago

4 0

Answer:

Explanation:

The fundamental mode of the standing wave in string is expressed as;

fo

F = V/2L where;

V is the speed of the transverse wave

L is the length of the string

Given

V = 40.0m/s

L = 2.00m

F = 40.0/2(2)

F = 40/4

F = 10Hertz

Hence the fundamental mode of the standing wave is 10Hz

<em></em>

<em>Overtone/harmonics are integral multiples of the fundamental frequency.</em>

Note that 1st overtone is also called second harmonic

Second harmonic

First overtone F1 = 2F

Second overtone/Third harmonics = 3F

First overtone F1 = 2*10

First overtone = 20Hz

3rd harmonic = 3*10

3rd harmonic = 30Hz

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