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lara [203]
3 years ago
7

Calculate the force it would take to accelerate a 50 kg bike at a rate of 3 m/s2.

Physics
1 answer:
Ede4ka [16]3 years ago
4 0

ummmm it might be 300... i used a calculator

sorry if it is wrong

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Two particles, each of mass m, are initially at rest very far apart.Obtain an expression for their relative speed of approach at
PSYCHO15rus [73]

Answer:

|\Delta v |=\sqrt{\frac{4Gm}{d} }

Explanation:

Consider two particles are initially at rest.

Therefore,

the kinetic energy of the particles is zero.

That initial K.E. = 0

The relative velocity with which both the particles are approaching each other is Δv and their reduced masses are

\mu= \frac{m_1m_2}{m_1+m_2}

now, since both the masses have mass m

therefore,

\mu= \frac{m^2}{2m}

= m/2

The final K.E. of the particles is

KE_{final}=\frac{1}{2}\times \mu\times \Delta v^2

Distance between two particles is d and the gravitational potential energy between them is given by

PE_{Gravitational}= \frac{Gmm}{d}

By law of conservation of energy we have

KE_{initial}+KE_{final}= PE_{gravitaional}

Now plugging the values we get

0+\frac{1}{2}\frac{m}{2}\Delta v^2= -\frac{Gmm}{d}

|\Delta v |=\sqrt{\frac{4Gm}{d} }

=\sqrt{\frac{Gm}{d} }

This the required relation between G,m and d

5 0
3 years ago
“Is it correct to say that a radio wave can be considered a low-frequency light wave?
klio [65]

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However, a radio wave CAN'T also be considered to be a sound wave.  These two things are as different as two waves can be.

-- Radio is an electromagnetic wave. Sound is a mechanical wave.

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-- Radio waves are transverse waves. Sound waves are longitudinal waves.

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-- Radio waves can be detected by radio, TV, and microwave receivers. Sound waves can't.

-- Sound waves can be detected by our ears. Radio waves can't.

-- Sound waves can be generated by talking, or by hitting a frying pan with a spoon. Radio waves can't.

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4 0
4 years ago
A scientist records the motion of an object. She writes down that the
Phantasy [73]
The answer is Velocity
3 0
3 years ago
​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If th
nadezda [96]

Answer:

distance when the weight is 8 ​kg is 26.66 cm

Explanation:

given data

distance d2 = 10 cm

weight w2 = 3 ​kg

weight w1 = 8 kg

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solution

we consider here distance d1 when weight is 8 kg

so equation will be

d1/d2 = w1/w2

d/10 = 8/ 3

so d = 8/3 × 10

so d = 26.66

distance when the weight is 8 ​kg is 26.66 cm

7 0
3 years ago
Help! 20 points of a test!
mamaluj [8]

Answer:

t=6

Explanation:

Multiply to remove the variable from the denominator.

4 0
3 years ago
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