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3 years ago

Calculate the force it would take to accelerate a 50 kg bike at a rate of 3 m/s2.

Physics

1 answer:

Ede4ka [16]3 years ago

4 0

ummmm it might be 300... i used a calculator

sorry if it is wrong

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Two 100kg bumper cars are moving towards eachother in oppisite directions. Car A is moving at 8 m/s and Car B at -10 m/s when th

DerKrebs [107]

Answer:

$-10 m/s$

Explanation:

When two cars collide then the momentum of two cars will remains conserved

Mass of two cars = 100 kg

Speed of car A = 8 m/s

Speed of car B = - 10 m/s

After collision the speed of car B = +8 m/s

By momentum conservation equation

$m1v1i+m2v2i=m1v1f + m2v2f$

$(100)(8)+(100)(-10)=(100v)+(100)(8)\\ v=-10 m/s$

7 0

3 years ago

A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.

trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = $\sqrt{16^{2}+2^{2}}$ = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity = $\sqrt{18^{2}+14^{2}}$ = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0

4 years ago

A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red

Alik [6]

Answer:

Speed of physicist car is 0.036c or 1.08 x 10⁷ m/s .

Explanation:

Doppler Effect is defined as the change in frequency or wavelength of the wave as the source or/and observer moving away or towards each other.

In this case, the Doppler effect equation in terms of wavelength is :

$\lambda_{s} = \lambda_{o}\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }$ ......(1)

Here $\lambda_{s}$ is source wavelength, $\lambda_{o}$ is observed wavelength, v is speed of the observer and c is the speed of light.

Given :

Source wavelength, $\lambda_{s}$ = 660 nm = 660 x 10⁻⁹ m

Observed wavelength, $\lambda_{0}$ = 555 nm = 555 x 10⁻⁹ m

Substitute these values in the equation (1).

$555\times10^{-9} } = 660\times10^{-9} \sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }$

$\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = 0.84$

${\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = (0.84)^{2} = 0.7056$

$1-\frac{v}{c}=0.7056+0.7056\frac{v}{c}$

$\frac{v}{c}=\frac{0.2944}{8.056}$

$v = 0.036c=0.036\times3\times10^{8}$

v = 1.08 x 10⁷ m/s

8 0

3 years ago

Which of the following describes the magnetic field produced by a current carrying wire? Assume the wire is normal to the page,

Maslowich

D) the magnetic field surrounds the wire like a tube , with a counterclockwise field direction...
as it is in the left hand thumb rule

6 0

3 years ago

Sophie applies a 50 n force to push a box 2 meter across the floor calculate the smount of work done in the box

kicyunya [14]

Work done = force x distance

Work done = 50 x 2

Work done = 100J

4 0

3 years ago