All categories

3 years ago

This chemical equation represents a ______________ reaction.

Physics

2 answers:

Ede4ka [16]3 years ago

7 0

Answer:

you didnt put anything

Explanation:

BARSIC [14]3 years ago

3 0

Yess yess it’s correct !!!!

You might be interested in

Burning coal produces which type of gas?

Aleksandr [31]

Answer:

carbon dioxide

Explanation:

In addition to carbon dioxide, discussed below, coal plants all produce the following pollutants: Sulfur dioxide, which leads to acid rain. Coal combustion is the leading source of US sulfur dioxide emissions. Nitrogen oxides, key contributors to ground-level ozone (smog) and respiratory illnesses.

6 0

3 years ago

Read 2 more answers

A 1380 kg car starts from rest at the

Ulleksa [173]

Answer: 72200

Explanation:

First you must find the height for this is on an inclined hill using:

h=Lsin(angle) —> 28.0sin(11.0) = 5.34

Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.

Using mgh:

m=1380

g=9.80

h=5.34

(1380)(9.8)(5.34)

=72218.16

*Rounding to the 3rd=72200

Hope this helps :)

6 0

2 years ago

Flash floods can cause vehicles to float and fill with water, trapping and drowning people. while especially dangerous at night

almond37 [142]

Answer:

Option (C)

Explanation:

Flash flood refers to the sudden flood that occurs in a particular area due to the heavy and excessive amount of rainfall, often accompanied by thunderstorms within a few hours. It releases a huge amount of water due to the failure of natural levee as well dam. They are very devastating. During flash flood, the water exerts a massive force which can make vehicles float over water. The six inches of water that flows over an area has the capacity to lift the tyres of small vehicles and carry hem further away.

Thus, the correct answer is option (C).

8 0

3 years ago

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.8×106N , one an angle 11degrees west of north an

sp2606 [1]

Answer: 2,9 ×10¹⁰J.

Explanation:

1. The work is a measure of energy and is calculated as the product of the displacement times the parallel force to such displacement.

That means that the only components of the force that contribute to work are those that result parallel to the displacement.

2. Since it is given that the two tugboats "pull the tanker a distance 0.83km toward the north", that is the displacement, and you have to calculate the net force toward the north.

3. Tugboat #1.

a) Force magnitude: F₁ = 1.8×10⁶N

b) Angle: α = 11° West of North

c) North component of the force F₁: Fy₁ = F₁cos(α) = 1.8×10⁶N × cos(11°) = 1.77×10⁶N

4. Tugboat #2:

a) Force magnitude: F₂ = 1.8×10⁶N

b) Angle: = 11° East of North

c) North component of the force F₂: Fy₂ = F₂cos(β) = 1.8×10⁶N × cos(11°) = 1.77×10⁶N =

5. Total net force, Fn:

Fn = Fy₁ + Fy₂ = 1.77×10⁶N + 1.77×10⁶N = 3.54×10⁶N

6. Work, W:

Displacement, d = 0.83 km = 8,300 m

W = Fn×d = 3.54×10⁶N×8,300m = 29,000 ×10⁶J = 2,9 ×10¹⁰J

The answer is rounded to two significant figures because both data, Force and displacement, have two significant figures.

7 0

3 years ago

How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?

gtnhenbr [62]

Answer:

W = 47040 J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040 J

So, the required work done is 47040 J.

7 0

3 years ago