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2 years ago

This chemical equation represents a ______________ reaction.

Physics

2 answers:

Ede4ka [16]2 years ago

7 0

Answer:

you didnt put anything

Explanation:

BARSIC [14]2 years ago

3 0

Yess yess it’s correct !!!!

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A doctor who specializes in the area of skin health is a dermatologist

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2 years ago

What are the four components to a workout program?

SSSSS [86.1K]

Answer:

Aerobic Fitness. Aerobic fitness improves overall health and well-being. ...

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Stability and Balance

Explanation:

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2 years ago

A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity

Likurg_2 [28]

Answer:

a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,

b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches = 0.0508 m

n = 1750 rpm

$H_{nom}=2hp=1491.4W$

L = 9 ft = 2.7432 m

Ks = 1.25

g = 9.81 m/s²

$w=\gamma b t = 9500* 0.1524*0.0013=1.88N/m$

$V=\frac{\pi d n}{60} =\pi *0.0508*1750/60=4.65 m/s$

$F_c=\frac{wV^2}{g}=1.88*4.65^2/9.81=4.15N$

$(F_1)_a=bF_aC_pC_v=0.1524*6000*0.7*1=640N$

$T=\frac{H_{nom}n_dK_s}{2\pi n}= \frac{1491*1.25*1}{2*\pi*1750/60}=10.17Nm$

$F_2=(F_1)_a-\frac{2T}{D}= 640-\frac{2*10.17}{0.0508} =239.6N$

$F_i=\frac{(F_1)_a+F_2}{2} -F_c=435.65N$

$H_a=1491*1.25=1863.75W$

$n_f_s=\frac{H_a}{H_{nom}K_S }=1$

dip = $\frac{L^2w}{8F_i} =\frac{2.7432*1.88}{435.65}=11.8mm$

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2 years ago

1Which of the following components of blood would you expect to see in higher

olga55 [171]

White blood cells(b) :)

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2 years ago

A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 63 Btu of heat is tr

jolli1 [7]

Answer:

The water would have a change in the energy of 50 BTU

Explanation:

Under the assumption that the piston-cylinder system is a closed system, then the conservation law of the system would be: $E_{in}-E_{out}=E_{change}$ , where $E_{in}$ is all the energy that goes into the system, $E_{out}$ is all the energy that leaves the system and, $E_{change}$ is the change of the energy of the system.
For this case the energy that is feeded to the system is heat: 63 BTU.
There is two ways that energy is leaving this system: 8 BTU of heat as losses through the side walls and, 5 BTU of work done by the vapor on the piston.
Then the change of energy of the system is: $E_{change}=E_{in}-E_{out}=63 BTU-(8BTU+5BTU)=50BTU$ .

6 0

2 years ago