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blsea [12.9K]
2 years ago
11

This chemical equation represents a ______________ reaction.

Physics
2 answers:
Ede4ka [16]2 years ago
7 0

Answer:

you didnt put anything

Explanation:

BARSIC [14]2 years ago
3 0
Yess yess it’s correct !!!!
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What is the correct reason for blinking / flickering of stars? Explain it.
Rzqust [24]

Answer:

d. changing refractive index of gases in the atmosphere

Explanation:

light from a star passes through the atmosphere to reach our eyes. however, the layers of gases in the atmosphere are in constant motion, so the light gets bent and appears to be flickering.

i hope this helps! :D

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2 years ago
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3 years ago
Read 2 more answers
A spring-loaded toy gun is used to shoot a ball of mass 1.5 kg straight up in the air, as shown. The spring has spring constant
asambeis [7]

Answer:

Part a)

U = 15.5 J

Part b)

h = 1.05 m

Part c)

v = 4.55 m/s

Explanation:

Part a)

Initial potential energy stored in the spring is given by

U = \frac{1}{2}kx^2

now we have

k = 777 N/m

x = 20.0 cm

now from above formula we will have

U = \frac{1}{2}(777)(0.20)^2

U = 15.5 J

Part b)

By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position

\frac{1}{2}kx^2 = mgh

15.5 = 1.5(9.8)h

h = 1.05 m

So maximum height from gun is 1.05 m

Part c)

For muzzle velocity of the ball we can use the energy conservation again

According to which the final kinetic energy of the ball = initial spring energy stored in it

\frac{1}{2}mv^2 = \frac{1}{2}kx^2

(\frac{1}{2})(1.5 v^2) = 15.5

v = v = 4.55 m/s

4 0
2 years ago
A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0
sergey [27]

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\frac{1}{2}m(v^2-u^2)

Using the formula

Work done, W=\frac{1}{2}(0.145)((25)^2-0)

Work done=\frac{1}{2}(0.145)(625)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

3 0
2 years ago
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