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2 years ago

A pyramid and a cone are both 12 centimeters tall and have the same

Mathematics

1 answer:

GarryVolchara [31]2 years ago

8 0

Answer:

The horizontal cross-sections of the prisms at the same height must have the same area.

Step-by-step explanation:

A pyramid and a cone are both 12 centimeters tall and have the same volume.... What is the volume?

Volume is the quantification of the three-dimensional space a substance occupies.

We have to determine the true statement, and it is

The horizontal cross-sections of the prisms at the same height must have the same area cone and given pyramid are looks like same in two-dimensional.

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Eliminate the x and y

sp2606 [1]

Step-by-step explanation:

Eliminate the x:

$\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by (-3)}\\\\\left\{\begin{array}{ccc}-3(x-2y)=(-3)(6)\\3x+y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-3x+6y=-18\\3x+y=4\end{array}\right}\\.\qquad\qquad7y=-14\\.\qquad\qquad y=-2$

Eliminate the y:

$\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by 2}\\\\\left\{\begin{array}{ccc}x-2y=6\\2(3x+y)=(2)(4)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=6\\6x+2y=8\end{array}\right}\\\\.\qquad7x=14\\.\qquad x=2$

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2 years ago

A person is strolling along a moving walkway at a constant velocity of +1.00 m/s with respect to the walkway, which moves at a c

Bezzdna [24]

Refer to the diagram shown below.

The velocity of the person on the walkway relative to the ground is the velocity of the walkway (relative to the ground) plus the velocity of the person relative to the walkway.
It is
1.0 + 0.5 = 1.5 m/s

The person on the ground moves at - 0.2 m/s, which is in the opposite direction to that of the walkway and the person on the walkway.
Therefore the velocity of the person on the walkway relative to the person on the ground is
105 - (-0.2) = 1.7 m/s

Answer: 1.7 m/s

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3 years ago

Plz help with math!!!

Orlov [11]

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3 years ago

A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t

Molodets [167]

Answer:

940.8 N

1254.4 N

Step-by-step explanation:

I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:

On the top:

F = pressure * area

P = density * gravity * height

the height would be:

1m - 0.4m = 0.6m

replacing:

P = 1000 * 9.8 * 0.6 = 5880

A = (0.4) ^ 2 = 0.16

F = 5880 * 0.16

F = 940.8 N

On the sides:

dF = d * g * h * dA

dA = 0.4 * dh replacing

dF = 1000 * 9.8 * h * 0.4 * dh

dF = 3920 * h * dh

We integrate both sides and we have:

F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1

F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)

F = 1254.4 N

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3 years ago

Solve by using the quadratic formula: Simplify

larisa [96]

Answer:

-6 - square root 31, -6 + square root 31

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2 years ago

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