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loris [4]
3 years ago
12

PLZ ANSWER I CAN'T FAIL

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

I say 36 girls, i divided 3 by 5 and multiplied it by 60,  so subtract 36 by 60, so there should be 24 boys

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Selina is planning to paint a large picture on a wall. She draws a smaller version first. The drawing is 8 inches by 6 inches. I
stich3 [128]
    Do you have a graph or of any sort with this question? If so that would help a lot!
6 0
3 years ago
The sum of Scott's age and Greg's age is 33. If Greg is represented by g, Scott's age is represented by
salantis [7]

Answer:

g+s=33

Step-by-step explanation:

I'm not sure if this is 100% correct, because you did not finish the question not provide me with answer choices. But I believe the answer should something along these lines.

3 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.
Andrews [41]

Answer:

\displaystyle 7 = x

Step-by-step explanation:

Five is <em>one-eighth</em> of forty, so relatively proportional to that, <em>one-eighth</em> of twenty-four is three, so you do this:

24 = 2x + 10

- 10 - 10

__________

\displaystyle \frac{14}{2} = \frac{2x}{2} \\ \\ 7 = x

I am joyous to assist you anytime.

5 0
3 years ago
Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from
Lapatulllka [165]
<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

The area of a triangle is= \frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]

=|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|

=|-54| = 54 square units

The length of AC = \sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}

                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

5 0
3 years ago
Gio is solving the quadratic equation by completing the square 5x^2+15x-4=0 What's should gio do first?
Softa [21]
Gio should for sure devide everything by ^2 and then combine like terms.
5 1
3 years ago
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