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dexar [7]
3 years ago
14

I just need the Point-Slope Form equation

Mathematics
1 answer:
Alina [70]3 years ago
7 0

The point-slope equation formula is (y - y_1) = m(x - x_1), where m is the slope of the line and (x_1, y_1) is a point on the line.


In our problem, we are adding $200 for each week x, or we are changing each week by +200. This means that our slope m, which is essentially the change of the line, is 200. The problem also gave us a coordinate point on the line, which was that at week 4, or when x = 4, we have $1700 in the account, or y = 1700. Thus, the coordinate point is (4, 1700).


Using this information, we can find the equation of the line:

(y - 1700) = 200(x - 4)


The answer is (y - 1700) = 200(x - 4).

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8/10 or 4/5 of an hour
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3 years ago
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You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o
anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0

\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

8 0
3 years ago
Which values from the set{5,7,9,11,13} make the inequality w-4<8 true?
Rasek [7]

Answer:

5, 7, 9, 11

Step-by-step explanation:

Solve the inequality

w - 4 < 8 ( add 4 to both sides )

w < 12

w ∈ { 5, 7, 9, 11 }

7 0
2 years ago
Find the length of the hypotenuse of a right triangle whose legs have lengths 4 and 8
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Ya gotta use the Pythagorean theorem :)

a² + b² = c²      (reminder: c is the hypotenuse)

4² + 8² = c²

16 + 64 = 80

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H = 8.94

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ASAP! I’ll give u Brainly !
kondor19780726 [428]

Answer:

I'm sorry but if your struggling with this iďk what to tell you chief

  • Its (1,5)
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