Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
I don't know the options but I guess it would be something like this:
40,000 < x < 50,000
Answer:
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
Step-by-step explanation:
For n=6 the degrees of freedom will be n-1 = 5 .
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
The critical region depends on ∝ and the alternative hypothesis
a) When Ha is σ²≠σ² the critical region is
χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test
( χ² < 0.83) and ( χ² > 0.83)
b) When Ha is σ²> σ² the critical region falls in the right tail and its value is
χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}
c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value
χ²(1-∝)(n-1) One tailed test (1.145)
Answer:
it is irrational,because the product of an irrational number and a non zero rational number is irrational
Answer: x=−3 or x=13
Step-by-step explanation:
Step 1: Subtract 39 from both sides.
x2−10x−39=39−39
x2−10x−39=0
Step 2: Factor left side of equation.
(x+3)(x−13)=0
Step 3: Set factors equal to 0.
x+3=0 or x−13=0
x=−3 or x=13
