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marishachu [46]
3 years ago
7

Solve x^2 – 8x + 41 = 0 for x.

Mathematics
1 answer:
icang [17]3 years ago
5 0
<span>\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i</span>
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Step-by-step explanation:

* Lets revise the empirical rule

- The Empirical Rule states that almost all data lies within 3

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- 95% of the data lies within two standard deviations.  

- 99.7% of the data lies Within three standard deviations  

- The empirical rule shows that

# 68% falls within the first standard deviation (µ ± σ)

# 95% within the first two standard deviations (µ ± 2σ)

# 99.7% within the first three standard deviations (µ ± 3σ).

* Lets solve the problem

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* <em>95% of the data lies between 24.8 and 49.6</em>

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