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marishachu [46]
3 years ago
7

Solve x^2 – 8x + 41 = 0 for x.

Mathematics
1 answer:
icang [17]3 years ago
5 0
<span>\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i</span>
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4x-5=4x+10 solve for x
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3 years ago
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3

Step-by-step explanation:

Triangles with the same shape but different size are proportional. Proportional means that their side lengths form equal ratios. To solve for x, set up a proportion.

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What is the equation of the line with a slope of 1/4 and a y-intercept of 2?
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Sanjay C.
6 0
3 years ago
Read 2 more answers
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