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ANEK [815]
3 years ago
13

Complete factorization of 6x^2?

Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

complete factorization. one in which all polynomial factors (excluding monomial factors) are prime; for example, the factorization of 4x² + 8x - 60 to 4(x² + 2x - 15) is not complete because the trinomial x² + 2x - 15 can itself be factored.

Step-by-step explanation:

hope this helps you :)

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Which statement is true?
Taya2010 [7]

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The sum of 78 and -78 is zero.

Step-by-step explanation:

I used a calculator ;)

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3 years ago
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What is the remainder when f(x) is divided by x-2 given that f(x)=4x^3-2x^2+x-13?​
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13

Step-by-step explanation:

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3 years ago
What is the fraction 24/4 simplified?
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3 years ago
Adam has created a register for the bank account he opened on April 16th. Unfortunately, Adam has made a mistake and cannot figu
sesenic [268]

Answer:

<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>

Step-by-step explanation:

1. Let's review the information given to us to help Adam to determine where his error is.

A. He completely forgot to include the clothes he bought from Bargains RUS. No, he didn't. It was recorded properly,  including the sales tax amount.

B. He made an arithmetic error in the balance column. No he didn't, the balance was calculated correctly after each transaction.

C. He recorded one of his withdrawals in the deposit column. No, he didn't. All of the withdrawals are in the right column.

<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>

8 0
3 years ago
Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?
ziro4ka [17]
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right
5 0
3 years ago
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