To find out how many chaperones are needed we need to know the multiples of 6.
6<span>,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102
Counting how many times 6's go into 53, we get 9.
We will need 9 chaperones!
I hope that helps!</span>
Step-by-step explanation:
3x + 1 = 5x
Bringing like terms on one side
1 = 5x - 3x
1 = 2x
1/2 = x
Hello from MrBillDoesMath!
Answer:
1/243
Discussion:
3^(-3) * 3^(-2) => as a^m * a^n = a^(m+n), the exponents add
= 3^ (-3 -2)
= 3^ (-5) =
= 1/ 3^5 => as 3^5 = 243
= 1/243
which is approximately .0041
Thank you,
MrB
Answer: choice B
Explanation: Go through each answer choice and try the Pythagorean theorem to see if it works. This is because a right triangle’s side lengths are described by the Pythagorean theorem. one side^2 + second side^2 = longest side^2. In a right triangle, this equation will be true. Let me show you what I mean
For answer choice A:
(root 2)^2 + (root 3)^2 = (root 4)^2
2 + 3 = 4
5 = 4
5 does not equal 4. Therefore it cannot be A.
For answer choice B:
(root 8)^2 + (3)^2 = (root 17)^2
8 + 9 = 17
17 = 17
this is true! therefore this is a right triangle and it’s B
<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
