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expeople1 [14]
2 years ago
10

Find the indicated term of the arithmetic sequence will give brainliest

Mathematics
2 answers:
Anettt [7]2 years ago
5 0

Answer:

103

Step-by-step explanation:

Q6 =

3+(21-1)5 = 103

Volgvan2 years ago
3 0

Answer:

A) in the relationship the rates of go cost course is given by d=2

So Since, the cost of

1. Lap= 2 $

2.Lap= 2 x 2 = 4 $

3.Lap= 4 + 2 = 6 $

4.Lap= 6 + 2 = 8 $

B) The (n) term of the sequence 2,4,6,8,... with, a,= 2,d= 2 is

a(n) = a,1 + (n - 1)d Write the formula

a(n) = 2 + (n - 1)2 Substitute values

a(n) = 2 + 2,n-2 Simplify

a(n) = 2n

Therefore, the (n) term of the sequence is a(n) = 2(n)

Step-by-step explanation:

I hope this helps at least for A and B

You might be interested in
Let ​ f(x)=x2+5x−36 ​. Enter the x-intercepts of the quadratic function in the boxes.
san4es73 [151]
Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-5*x-(36)=0 

Step by step solution:<span> Step 1:</span> Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-5x-36</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is 1.
The middle term is, <span> -5x </span> its coefficient is  - 5.
The last term, "the constant", is <span> -36 </span>

Step-1: Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2: Find two factors of  -36  whose sum equals the coefficient of the middle term, which is - 5.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9</span><span>     -9   +   4   =   -5   That's it</span></span>


Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  4 
                     <span>x2 - 9x</span> + 4x - 36

Step-4: Add up the first 2 terms, pulling out like factors :
                    x • (x-9)
              Add up the last 2 terms, pulling out common factors :
                    4 • (x-9)
Step-5: Add up the four terms of step 4 :
                    (x+4)  •  (x-9)
             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x + 4) • (x - 9) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     x = -4 

Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-9 = 0<span> 

 </span>Add  9  to both sides of the equation :<span> 
 </span>                     x = 9 

6 0
3 years ago
Read 2 more answers
Y intercepts of 3x^2-12x+6
Inessa05 [86]
Y=3x^2. -12x+6

If x= 0 then y= 3•0^2 -12•0+6=6
X=0, y=6

y intercept is the place where the curve touches the y-axis and is at point (0, 6)
6 0
3 years ago
3w-4z=8
Nezavi [6.7K]
W=0
Z=-2
Is there a need for explanation?
8 0
3 years ago
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
Geometry help greatly needed. please help if possible.
elixir [45]

Answer:

\huge\boxed{\sf  x = 90\°}

Step-by-step explanation:

If AB is diameter, the angle opposite to it, when a triangle is inscribed in that semi circle, will be 90 degrees.

<u>Given that:</u>

AB is the diameter.

According to what is given, we come to know that <ACB = x = 90°.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
2 years ago
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