Question

Two charges: q1=5C and q2= -3C are separated by 3.6 * 10^-6m. What is the force between them? Do the charges repel or attract?

Answer 1

Answer:

F = - 10.417 × 10²¹ N

since, the charges are opposite in nature, thus they will attract.

Step-by-step explanation:

Data provided in the question:

charges

q₁ = 5 C

q₂ = -3 C

r = 3.6 × 10⁻⁶ m

now,

the force (F) between the two charges is given as:

$F=\frac{kq_1q_2}{r^2}$

k is the coulomb's constant = 9 × 10⁹ N·m²/C²

on substituting the values, we get

$F=\frac{9\times10^9\times5\times(-3)}{(3.6\times10^{-6})^2}$

or

F = - 10.417 × 10²¹ N

since, the charges are opposite in nature, thus they will attract.