Two charges: q1=5C and q2= -3C are separated by 3.6 * 10^-6m. What is the force between them? Do the charges repel or attract?
1 answer:
Answer:
F = - 10.417 × 10²¹ N
since, the charges are opposite in nature, thus they will attract.
Step-by-step explanation:
Data provided in the question:
charges
q₁ = 5 C
q₂ = -3 C
r = 3.6 × 10⁻⁶ m
now,
the force (F) between the two charges is given as:
k is the coulomb's constant = 9 × 10⁹ N·m²/C²
on substituting the values, we get
or
F = - 10.417 × 10²¹ N
since, the charges are opposite in nature, thus they will attract.
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