The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
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6x^2y^3
= 2( 5y^2 - 2x)
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6x^2y^3
= 5y^2 - 2x
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3x^2y^3
Answer:
4/16
Step-by-step explanation:
pls give me brainliest
Answer:
3
Step-by-step explanation:
First, subtract 4 from both sides. When you do this, that leaves you with: 3x=9. Then, divide 9 by 3 to get x by itself. x=3
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
