Answer:
1,044
Step-by-step explanation:
Answer:
1. cos (x/2)
2.y=cos(4x)
3. y=cos(x)
4.y= cos(x/4)
Step-by-step explanation:
The graph of cosine function is sinusoidal and the y value ranges between -1 to 1.
the cosine function is periodic with general period P of 2π
if P< 2π then cosine graph experience a compression horizontally
if P>2π then cosine graph experience a stretch horizontally
for graph 1, the period is 4π hence the graph is stretched with period of 4π
for graph 2, the period is π/2 hence the graph is compressed with period of π/2
for graph 3, the period is 2π hence the graph is periodic with period of 2π
for graph 4, the period is 8π hence the graph is stretched with period of 4π
!
Answer:
294 in.²
Step-by-step explanation:
I believe this figure is a rectangular prism.
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<u>Explain:</u>
To find the surface area of a rectangular prism, use this formula:
or
A phrase I use to help remember this formula is:
LISA WILSON LOST HER WITCH HAT TWICE (2)
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<u>Solve:</u>
The length of this rectangular prism is 9 in.
This width is 10 in.
The height is 3 in.
Now, I will plug the numbers into the first formula.
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<u>Conclude:</u>
I, therefore, believe the area of this rectangular prism is 294 in.²
Answer:
You cant see the equation
Step-by-step explanation:
Answer:
y=1/2(x-1)
Step-by-step explanation:
If x=t^2 and t>0, then t=sqrt(x).
If t=sqrt(x) or x^(1/2) and y =1-1/t, then y=1-x^(-1/2).
The x-intercept is when y=0.
So we need to solve 0=1-x^(-1/2) to find point P.
Add x^(-1/2) on both sides: x^(-1/2)=1.
Raise both sides to -2 power: x=1
So point P is (1,0).
Let's find tangent line at point (1,0).
We will need the slope so let's differentiate.
y'=0+1/2x^(-3/2)
y'=1/(2x^(3/2))
The slope at x=1 is y'=1/(2[1]^(3/2))=1/(2×1)=1/2.
Recall point-slope form is y-y1=m(x-x1).
So our line we are looking for is y-0=1/2(x-1)
Let's simplify left hand side y=1/2(x-1)
